我的以下表单正常工作并填充 MySQL 数据库。此后，我在数据库中添加了一个新字段“类型”，并将其添加到表单中。但是现在，当我尝试添加新条目时，它显示“无效的列名‘类型’”。任何帮助将不胜感激。
<script>
$(document).ready(function() {
$("#datepicker").datepicker();
});
</script>
<script>
$(document).ready(function() {
$("#datepicker2").datepicker();
});
</script>
</head>
<body>
<?php
// if there are any errors, display them
if ($error != '')
{
echo '<div style="padding:4px; border:1px solid red; color:red;">'.$error.'</div>';
}
?>
<form action="" method="post">
<div>
<label for="Posted"><strong>Posted: </strong> </label>
<input id="datepicker" name="posted" value="<?php echo $Posted; ?>" /><br/><br/>
<label for="Ends"><strong>Ends: </strong> </label>
<input id="datepicker2" name="ends" value="<?php echo $Ends; ?>" /><br/><br/>
<label for="Position"><strong>Position: </strong></label>
<input type="text" name="position" value="<?php echo $Position; ?>" /><br/><br/>
<label for="Location"><strong>Location: </strong> </label>
<select name="location">
<option value=" ">Select...<?php echo $Location; ?></option>
<option value="Fargo">Fargo</option>
<option value="Grand Forks">Grand Forks</option>
</select><br/><br/>
<label for="Application Type"><strong>Application Type: </strong> </label>
<select name="type">
<option value=" ">Select...<?php echo $Type; ?></option>
<option value="Driver">Driver</option>
<option value="Employee">Employee</option>
</select><br/><br/>
<label for="Hours"><strong>Hours: </strong> </label>
<input type="text" name="hours" value="<?php echo $Hours; ?>" /><br/><br/>
<label for="Pay"><strong>Pay: </strong> </label>
<input type="text" name="pay" value="<?php echo $Pay; ?>" /><br/><br/>
<label for="Benefits"><strong>Benefits: </strong> </label>
<textarea cols="60" rows="2" name="benefits" value="<?php echo $Benefits; ?>" ><?php echo $Benefits; ?></textarea><br/><br/>
<label for="Description"><strong>Description: </strong> </label>
<textarea cols="60" rows="3" name="description" value="<?php echo $Description; ?>" ><?php echo $Description; ?></textarea><br/><br/>
<input type="submit" name="submit" value="Submit">
</div>
</form>
</body>
</html>
<?php
}
// connect to the database
include('connect-db.php');
// check if the form has been submitted. If it has, start to process the form and save it to the database
if (isset($_POST['submit']))
{
// get form data, making sure it is valid
function ms_escape_string($data) {
if ( !isset($data) or empty($data) ) return '';
if ( is_numeric($data) ) return $data;
$non_displayables = array(
'/%0[0-8bcef]/', // url encoded 00-08, 11, 12, 14, 15
'/%1[0-9a-f]/', // url encoded 16-31
'/[\x00-\x08]/', // 00-08
'/\x0b/', // 11
'/\x0c/', // 12
'/[\x0e-\x1f]/' // 14-31
);
foreach ( $non_displayables as $regex )
$data = preg_replace( $regex, '', $data );
$data = str_replace("'", "''", $data );
return $data;
}
ms_escape_string($_POST);
$posted=$_POST['posted'];
$ends=$_POST['ends'];
$type=$_POST['type'];
$position=$_POST['position'];
$location=$_POST['location'];
$hours=$_POST['hours'];
$pay=$_POST['pay'];
$benefits=$_POST['benefits'];
$description=$_POST['description'];
// check to make sure all fields are entered
if ($posted == '' || $ends == '' || $type == '' || $position == '' || $location == '' || $hours == '' || $pay == '' || $benefits == '' || $description == '')
{
// generate error message
$error = 'ERROR: Please fill in all required fields!';
// if any fields are blank, display the form again
renderForm($posted, $ends, $type, $position, $location, $hours, $pay, $benefits, $description, $error);
}
else
{
// save the data to the database
$SQL = "INSERT INTO JobPosting (posted, ends, type, position, location, hours, pay, benefits, description) VALUES ('$posted', '$ends', '$type', '$position', '$location', '$hours', '$pay', '$benefits', '$description')";
$result = mssql_query($SQL)
or die (mssql_get_last_message());
// once saved, redirect back to the view page
header("Location: view.php");
}
}
else
// if the form hasn't been submitted, display the form
{
renderForm('','','','','','','','','','');
}
最佳答案
您需要在查询中转义列名type，即type，因为type是MySQL sytax中的保留工作。
你到底如何逃脱`标记？
关于php - mysql PHP 查询中的列名无效，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/13038942/