sql-server - T SQL For XML PATH Group By 作为属性或元素

Question

我一直在使用 T-SQL FOR XML with PATH Mode 来创建基于字段分组的层次结构。 以下是我的查询和输出。请帮我提出宝贵的建议。谢谢你。再会!!!

select e.department_id AS [@DepartmentID],
d.DEPARTMENT_NAME AS [@DepartmentName],
e.EMPLOYEE_ID AS [EmployeeInfo/EmployeeID],
e.FIRST_NAME AS [EmployeeInfo/FirstName],
e.LAST_NAME AS [EmployeeInfo/LastName]
from employees e
JOIN departments d 
ON e.department_id = d.department_id
GROUP BY e.department_id,d.DEPARTMENT_NAME,
e.EMPLOYEE_ID,e.FIRST_NAME,e.LAST_NAME
FOR XML PATH ('Department'), ROOT ('Departments')

输出:

 <Departments>
  <Department DepartmentID="10">
    <EmployeeInfo>
      <EmployeeID>111</EmployeeID>
      <FirstName>John</FirstName>
      <LastName>Chen</LastName>
    </EmployeeInfo>
  </Department>
  <Department DepartmentID="10">
    <EmployeeInfo>
      <EmployeeID>201</EmployeeID>
      <FirstName>steven</FirstName>
      <LastName>Whalen</LastName>
    </EmployeeInfo>
  </Department>
  <Department DepartmentID="30">
    <EmployeeInfo>
      <EmployeeID>105</EmployeeID>
      <FirstName>ANIRUDH</FirstName>
      <LastName>RAMESH</LastName>
    </EmployeeInfo>
  </Department>
  <Department DepartmentID="30">
    <EmployeeInfo>
      <EmployeeID>115</EmployeeID>
      <FirstName>Den</FirstName>
      <LastName>Raphaely</LastName>
    </EmployeeInfo>
  </Department>
<Departments>

期望的输出是:

<Departments>
  <Department DepartmentID="10">
    <EmployeeInfo>
      <EmployeeID>111</EmployeeID>
      <FirstName>John</FirstName>
      <LastName>Chen</LastName>
    </EmployeeInfo>
    <EmployeeInfo>
      <EmployeeID>201</EmployeeID>
      <FirstName>steven</FirstName>
      <LastName>Whalen</LastName>
    </EmployeeInfo>
  </Department>
  <Department DepartmentID="30">
    <EmployeeInfo>
      <EmployeeID>105</EmployeeID>
      <FirstName>ANIRUDH</FirstName>
      <LastName>RAMESH</LastName>
    </EmployeeInfo>
    <EmployeeInfo>
      <EmployeeID>115</EmployeeID>
      <FirstName>Den</FirstName>
      <LastName>Raphaely</LastName>
    </EmployeeInfo>
  </Department>
<Departments>

Answer 1

你可以使用 TYPE对于嵌套的 xml

SELECT 
      d.department_id AS [@DepartmentID],
      d.DEPARTMENT_NAME AS [@DepartmentName], 
      (
         SELECT 
                e.EMPLOYEE_ID AS EmployeeID,
                e.FIRST_NAME AS [FirstName],
                e.LAST_NAME AS [LastName]  
         FROM employees e
         WHERE e.department_id = d.department_id
         FOR XML PATH ('EmployeeInfo'), TYPE
      )
FROM departments d 
FOR XML PATH ('Department'), ROOT ('Departments')