c# - 如何根据正则表达式将文本拆分为多行？

Question

我有一些文本片段，我想将它们分成几行。问题是它们已经被格式化，所以我不能像通常那样拆分:

 _text = text.Split(new[] { '\n' }, StringSplitOptions.RemoveEmptyEntries)
            .ToArray();

这是示例文本:

 adj 1: around the middle of a scale of evaluation of physical
        measures; "an orange of average size"; "intermediate
        capacity"; "a plane with intermediate range"; "medium
        bombers" [syn: {average}, {intermediate}]
 2: (of meat) cooked until there is just a little pink meat
    inside
 n 1: a means or instrumentality for storing or communicating
      information
 2: the surrounding environment; "fish require an aqueous
    medium"
 3: an intervening substance through which signals can travel as
    a means for communication
 4: (bacteriology) a nutrient substance (solid or liquid) that
    is used to cultivate micro-organisms [syn: {culture medium}]
 5: an intervening substance through which something is
    achieved; "the dissolving medium is called a solvent"
 6: a liquid with which pigment is mixed by a painter
 7: (biology) a substance in which specimens are preserved or
    displayed
 8: a state that is intermediate between extremes; a middle
    position; "a happy medium"

格式总是一样的:

• 可能存在 1-3 个字母的单词
• 1-10号
• 冒号
• 空间
• 可能出现在多行的文本。

因此在这种情况下，换行符必须类似于 1-3 个字符的单词，后跟 1-2 个字符的数字，然后是 :

有人可以给我一些建议，告诉我如何使用拆分或其他方法做到这一点吗？

更新:Steven 的回答，但不太确定如何将其纳入我的职能。在这里，我展示了我的原始代码，下面是史蒂文建议的答案，但缺少我不确定的部分:

    public parser(string text)
    {
        //_text = text.Split(new[] { '\n' }, StringSplitOptions.RemoveEmptyEntries)
            // .ToArray();

        string pattern = @"(\w{1,3} )?1?\d: (?<line>[^\r\n]+)(\r?\n\s+(?<line>[^\r\n]+))*";
        foreach (Match m in Regex.Matches(text, pattern))
        {
            if (m.Success)
            {
                string entry = string.Join(Environment.NewLine,
                    m.Groups["line"].Captures.Cast<Capture>().Select(x => x.Value));
                // ...
            }
        }
    }

出于测试目的，这里是不同格式的文本:

"medium\n adj 1: 围绕物理\n 措施评估范围的中间;\"平均大小的橙子\";\"中间\n 容量\";\"具有中间范围的平面\";\"medium\n bombers\"[syn: {average}, {intermediate}]\n 2: (of meat) cooked until there is just a little pink meat inside\n n 1: 一种手段或工具用于存储或通信\n 信息\n 2:周围环境；“鱼需要水性介质\n”\n 3:信号可以通过其传播\n 作为通信手段\n 4:(细菌学) 一种营养物质(固体或液体)，\n 用于培养微生物 [syn: {culture medium}]\n 5: 一种中间物质，通过它\n 可以达到某种目的；\n 溶解介质称为 a solvent\"\n 6: 画家将颜料与颜料混合的液体\n 7: (生物学) 一种物质，其中特定imens 被保留或显示\n 8:介于极端之间的状态；中间位置；\"a happy medium\"\n 9: 充当生者与死者之间的中介的人；\n\"他咨询了几种媒介\"[syn: {spiritualist}]\n 10: 向公众广泛传播的传播\n [syn: {mass medium}]\n 11: 你特别适合的职业;\"在法律上，他找到了自己真正的职业\"[syn: {metier}]\n [also: {media} (pl)]\n"

Answer 1

Regex 对此非常有用。例如:

public parser(string text)
{
    string pattern = @"(?<line> (\w{1,3} )?1?\d: [^\r\n]+)(\r?\n(?! (\w{1,3} )?1?\d: [^\r\n]+)\s+(?<line>[^\r\n]+))*";
    var entries = new List<string>();
    foreach (Match m in Regex.Matches(text, pattern))
        if(m.Success)
            entries.Add(string.Join(" ", 
                m.Groups["line"].Captures.Cast<Capture>().Select(x=>x.Value)));
    _text = entries.ToArray();
}