我正在尝试从 HttpServletRequest 对象中获取整个主体。
我正在关注的代码如下所示:
if ( request.getMethod().equals("POST") )
{
StringBuffer sb = new StringBuffer();
BufferedReader bufferedReader = null;
String content = "";
try {
//InputStream inputStream = request.getInputStream();
//inputStream.available();
//if (inputStream != null) {
bufferedReader = request.getReader() ; //new BufferedReader(new InputStreamReader(inputStream));
char[] charBuffer = new char[128];
int bytesRead;
while ( (bytesRead = bufferedReader.read(charBuffer)) != -1 ) {
sb.append(charBuffer, 0, bytesRead);
}
//} else {
// sb.append("");
//}
} catch (IOException ex) {
throw ex;
} finally {
if (bufferedReader != null) {
try {
bufferedReader.close();
} catch (IOException ex) {
throw ex;
}
}
}
test = sb.toString();
}
我正在使用 curl 和 wget 测试功能,如下所示:
curl --header "MD5: abcd" -F "fileupload=@filename.txt http://localhost:8080/abcd.html"
wget --header="MD5: abcd" --post-data='{"imei":"351553012623446","hni":"310150","wdp":false}' http://localhost:8080/abcd.html"
但是 while ( (bytesRead = bufferedReader.read(charBuffer)) != -1 )
没有返回任何内容,所以我没有在 StringBuffer 上附加任何内容。
最佳答案
在 Java 8 中,您可以用一种更简单、更简洁的方式来做到这一点:
if ("POST".equalsIgnoreCase(request.getMethod()))
{
test = request.getReader().lines().collect(Collectors.joining(System.lineSeparator()));
}
关于java - 从 HttpServletRequest 获取 POST 请求正文,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8100634/