c# - Websocket 服务器,客户端无法握手

标签 c# websocket listener

我正在使用最新版本的 Chrome(websocket 版本 13)进行测试。

这是我位于 http://127.0.0.1/folder/default.aspx 的简单客户端页面:

<script type="text/javascript">
    var socket = new WebSocket('ws://localhost:8181/websession');
    socket.onopen = function () {
        alert('handshake successfully established. May send data now...');
    };
    socket.onclose = function () {
        alert('connection closed');
    };
    socket.onmessage = function(msg) {
        alert(msg);
    };
</script>

这是我的监听器 (c#)

var listener = new TcpListener(IPAddress.Loopback, 8181);
listener.Start();
while (true)
{
    Console.WriteLine("Listening...");
    using (var client = listener.AcceptTcpClient())
    using (var stream = client.GetStream())
    using (var reader = new StreamReader(stream))
    using (var writer = new StreamWriter(stream))
    {
        writer.WriteLine("HTTP/1.1 101 Web Socket Protocol Handshake");
        writer.WriteLine("Upgrade: WebSocket");
        writer.WriteLine("Connection: Upgrade");
        writer.WriteLine("WebSocket-Origin: http://127.0.0.1");
        writer.WriteLine("WebSocket-Location: ws://localhost:8181/websession");
        writer.WriteLine("");
    }
    Console.WriteLine("Finished");
}

当我运行服务器,然后加载客户端页面时,它只显示"connection closed"

有人可以告诉我如何正确执行此握手吗?据我从文档和之前的问题中可以看出,我发回给客户的响应看起来是正确的。

最佳答案

根据您的代码,这应该可以工作(至少对于 chrome)

var listener = new TcpListener(IPAddress.Loopback, 8181);
listener.Start();
while (true)
{
    Console.WriteLine("Listening...");
    using (var client = listener.AcceptTcpClient())
    using (var stream = client.GetStream())
    using (var reader = new StreamReader(stream))
    using (var writer = new StreamWriter(stream))
    {

        string line = null, key = "", responseKey = "";
        string MAGIC_STRING = "258EAFA5-E914-47DA-95CA-C5AB0DC85B11";
        while (line != "")
        {
            line = reader.ReadLine();
            if (line.StartsWith("Sec-WebSocket-Key:"))
            {
                key = line.Split(':')[1].Trim();
            }
        }

        if (key != "")
        {
            key += MAGIC_STRING;
            using (var sha1 = SHA1.Create())
            {
                responseKey = Convert.ToBase64String(sha1.ComputeHash(Encoding.ASCII.GetBytes(key)));
            }
        }

        // send handshake to the client
        writer.WriteLine("HTTP/1.1 101 Web Socket Protocol Handshake");
        writer.WriteLine("Upgrade: WebSocket");
        writer.WriteLine("Connection: Upgrade");
        writer.WriteLine("WebSocket-Origin: http://127.0.0.1");
        writer.WriteLine("WebSocket-Location: ws://localhost:8181/websession");
        if (!String.IsNullOrEmpty(responseKey)) 
            writer.WriteLine("Sec-WebSocket-Accept: " + responseKey);
        writer.WriteLine("");

        writer.Flush();

        SendString(stream, "This code works!!!!");
        SendString(stream, "This code also works!!!! ".PadRight(300, '.') + "\r\nEND");
    }
    Console.WriteLine("Finished");
}


void SendString(Stream s, string str)
{
    var buf = Encoding.UTF8.GetBytes(str);
    int frameSize = 64;

    var parts = buf.Select((b, i) => new { b, i })
                   .GroupBy(x => x.i / (frameSize - 1))
                   .Select(x => x.Select(y => y.b).ToArray())
                   .ToList();

    for (int i = 0; i < parts.Count; i++ )
    {
        byte cmd = 0;
        if (i == 0) cmd |= 1;
        if (i == parts.Count - 1) cmd |= 0x80;

        s.WriteByte(cmd);
        s.WriteByte((byte)parts[i].Length);
        s.Write(parts[i], 0, parts[i].Length);
    }

    s.Flush();
}

附言:使用

socket.onmessage = function(msg) {
    alert(msg.data);
};

查看服务器发送的消息内容。

关于c# - Websocket 服务器,客户端无法握手,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13517712/

相关文章:

python - Django Channels 或 Tornado 用于基于套接字的连接

vector - OpenLayers 矢量层特征处理程序

c# - 无法加载 ps1,因为在此系统上禁用了运行脚本

c# - System.DateTime 种类位

c# - Arduino串口,数据未到达

c# - 有谁知道正则表达式中 ".*\s*"和 "[.\s]*"的区别吗?

javascript - Socket IO 中的确认与发出

unity3d - 使用 WebGL Unity 连接到 TCP 服务器

java - 监听 Javascript 函数调用 - Android

Java 在文件被修改时获取通知