c# - 在 C# cmdlet 中创建 PowerShell PSObject

Question

C# 新手，但有 PowerShell 经验。接管别人的代码。编写已编译的 PowerShell 模块，并尝试弄清楚如何根据返回的数据创建对象。现在，代码返回一个字符串:

ServerResponse<UCCSiteModel> requestModel = this.MakeRequest("/site/api/", "site", "GET", this.Credentials, queryString);
StringBuilder builder = new StringBuilder();

if (requestModel != null && requestModel.Response != null)
{
    builder.AppendLine("SiteID: " + requestModel.Response.SiteID);
    builder.AppendLine("Identity: " + requestModel.Response.SiteName);
    builder.AppendLine("Site Code: " + requestModel.Response.SiteCode);
    builder.AppendLine("Contact Name: " + requestModel.Response.ContactName);
    builder.AppendLine("Contact Number: " + requestModel.Response.ContactNumber);
    builder.AppendLine("Contact Email Address: " + requestModel.Response.ContactEmailAddress);
    builder.AppendLine("Address: " + requestModel.Response.Address);
    builder.AppendLine("City: " + requestModel.Response.City);
    builder.AppendLine("State: " + requestModel.Response.State);
    builder.AppendLine("Post Code: " + requestModel.Response.PostCode);
    builder.AppendLine("Time Zone: " + requestModel.Response.Timezone);
    builder.AppendLine("Longitude: " + requestModel.Response.longitude);
    builder.AppendLine("Latitude: " + requestModel.Response.latitude);                    
    this.WriteResponse(requestModel, builder.ToString());
}

如何从 requestModel.Response 创建一个对象而不是字符串发送回 PowerShell？在编写 PowerShell 时，我通常会使用 New-Object PsObject，然后使用 Add-Member。不确定如何在 C# 中执行此操作，也不确定它的名称(以便我可以搜索)。有人吗？

Answer 1

您可以通过在 PSObject< 的 Members 属性上调用 Add() 来简单地反射(reflect) Add-Member 的行为(为了便于在 PowerShell 中访问，我会将属性名称更改为 CamelCase):

if (requestModel != null && requestModel.Response != null)
{
    PSObject responseObject = new PSObject();

    responseObject.Members.Add(new PSNoteProperty("SiteID", requestModel.Response.SiteID));
    responseObject.Members.Add(new PSNoteProperty("Identity", requestModel.Response.SiteName));
    // and so on etc... 
    responseObject.Members.Add(new PSNoteProperty("Latitude", requestModel.Response.latitude));

    this.WriteObject(responseObject);
}