C# 比较字符串忽略大小写

Question

在此测试方法中，我需要比较 user3 的字符串，同时忽略区分大小写。我在想我应该使用 CultureInfo.InvariantCulture 来忽略大小写。这是实现此目标的最佳方法，还是有更好的方法？

            //set test to get user 
            AsaMembershipProvider prov = this.GetMembershipProvider();        

            //call get users
            MembershipUser user1 = prov.GetUser("test.user", false);
            //ask for the username with deliberate case differences
            MembershipUser user2 = prov.GetUser("TeSt.UsEr", false);
            //getting a user with Upper and lower case in the username.
            MembershipUser user3 = prov.GetUser("Test.User", false);

            //prove that you still get the user, 
            Assert.AreNotEqual(null, user1);
            Assert.AreNotEqual(null, user2);

            //test by using the “.ToLower()” function on the resulting string.
            Assert.AreEqual(user1.UserName.ToLower(), user2.UserName.ToLower());
            Assert.AreEqual(user1.UserName, "test.user");
            Assert.AreEqual(user3.UserName, "test.user");

Answer 1

使用 Assert.AreEqual使用 ignoreCase 参数更好，因为它不需要创建新字符串(并且，正如@dtb 所指出的，您可以按照特定文化信息的规则工作)

Assert.AreEqual(user1.UserName, user2.UserName, true, CultureInfo.CurrentCulture);