c# - 强密码的正则表达式

Question

我需要一个正则表达式，它至少包含以下五个字符类中的两个:

• 小写字符
• 大写字符
• 数字
• 标点符号
• “特殊”字符(例如 @#$%^&*()_+|~-=\{}[]:";'<>/` 等)

这是我到目前为止所做的

int upperCount = 0;
int lowerCount = 0;
int digitCount = 0;
int symbolCount = 0;

for (int i = 0; i < password.Length; i++)
{
    if (Char.IsUpper(password[i]))
        upperCount++;
    else if (Char.IsLetter(password[i]))
        lowerCount++;
    else if (Char.IsDigit(password[i]))
        digitCount++;
    else if (Char.IsSymbol(password[i]))
        symbolCount++;

但 Char.IsSymbol 在 @% & $ 上返回 false。 ？等..

并通过正则表达式

Regex Expression = new Regex("({(?=.*[a-z])(?=.*[A-Z]).{8,}}|{(?=.*[A-Z])(?!.*\\s).{8,}})");    
bool test= Expression.IsMatch(txtBoxPass.Text);

但我需要一个带有“OR”条件的正则表达式。

Answer 1

换句话说，您需要一个不只包含一“类”字符的密码。然后你可以使用

^(?![a-z]*$)(?![A-Z]*$)(?!\d*$)(?!\p{P}*$)(?![^a-zA-Z\d\p{P}]*$).{6,}$

解释:

^           # Start of string
(?![a-z]*$) # Assert that it doesn't just contain lowercase alphas
(?![A-Z]*$) # Assert that it doesn't just contain uppercase alphas
(?!\d*$)    # Assert that it doesn't just contain digits
(?!\p{P}*$) # Assert that it doesn't just contain punctuation
(?![^a-zA-Z\d\p{P}]*$) # or the inverse of the above
.{6,}       # Match at least six characters
$           # End of string