基本上是 this 的骗局有一个显着差异的问题 - 我必须使用 DataContractJsonSerializer。
一个简单的
using (var stream = new MemoryStream())
{
var serializer = new DataContractJsonSerializer(typeof(Person));
serializer.WriteObject(stream, obj);
...
return stream.ToArray();
}
生成单行 json，例如(保存在文件中时)
...{"blah":"v", "blah2":"v2"}...
制作它的选项有哪些
...
{
"blah":"v",
"blah2":"v2"
}
...
我可以想到后处理...有更简单的选择吗？例如。类似于格式化 xml produced by DataContractSerializer ？
using (var stream = new MemoryStream())
{
var serializer = new DataContractJsonSerializer(typeof(T));
// "beautify"
using (var writer = new SomeKindOfWriter(stream))
serializer.WriteObject(writer, obj);
...
return stream.ToArray();
}
有没有办法让这样的SomeKindOfWriter在需要的时候美化json？
https://stackoverflow.com/a/38538454/6627992
您可以使用以下标准方法获取格式化的 Json
JsonReaderWriterFactory.CreateJsonWriter(Stream 流, Encoding 编码, bool ownsStream, bool indent, string indentChars)
只设置"indent==true"
尝试这样的事情
public readonly DataContractJsonSerializerSettings Settings =
new DataContractJsonSerializerSettings
{ UseSimpleDictionaryFormat = true };
public void Keep<TValue>(TValue item, string path)
{
try
{
using (var stream = File.Open(path, FileMode.Create))
{
//var currentCulture = Thread.CurrentThread.CurrentCulture;
//Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
try
{
using (var writer = JsonReaderWriterFactory.CreateJsonWriter(
stream, Encoding.UTF8, true, true, " "))
{
var serializer = new DataContractJsonSerializer(type, Settings);
serializer.WriteObject(writer, item);
writer.Flush();
}
}
catch (Exception exception)
{
Debug.WriteLine(exception.ToString());
}
finally
{
//Thread.CurrentThread.CurrentCulture = currentCulture;
}
}
}
catch (Exception exception)
{
Debug.WriteLine(exception.ToString());
}
}
注意线条
var currentCulture = Thread.CurrentThread.CurrentCulture;
Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
....
Thread.CurrentThread.CurrentCulture = currentCulture;
对于某些类型的 xml 序列化程序，您应该使用 InvariantCulture 来避免在具有不同区域设置的计算机上反序列化期间出现异常。例如，double 或 DateTime 的无效格式有时会导致它们。
反序列化
public TValue Revive<TValue>(string path, params object[] constructorArgs)
{
try
{
using (var stream = File.OpenRead(path))
{
//var currentCulture = Thread.CurrentThread.CurrentCulture;
//Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
try
{
var serializer = new DataContractJsonSerializer(type, Settings);
var item = (TValue) serializer.ReadObject(stream);
if (Equals(item, null)) throw new Exception();
return item;
}
catch (Exception exception)
{
Debug.WriteLine(exception.ToString());
return (TValue) Activator.CreateInstance(type, constructorArgs);
}
finally
{
//Thread.CurrentThread.CurrentCulture = currentCulture;
}
}
}
catch
{
return (TValue) Activator.CreateInstance(typeof (TValue), constructorArgs);
}
}
谢谢!