我正在开发一个动态商店项目,我使用循环将产品的所有颜色选项打印为颜色框,但是我确实需要为这些浅色添加“边框”。我尝试了类似以下的方法,但它非常有限,实际上仅限于白色,它不会捕捉到 #ddd、#eea... 之类的东西
这是我的循环:
foreach($colors as $color) {
$color = trim($color);
if (!empty($color)) {
if (in_array($color, array('white','White','#fff','#FFF','#FFFFFF','#ffffff'))) {
$bordercolor = '#bbb';
} else {
$bordercolor = $color;
}
}
}
Colors 是来自后端的数组,例如:White、#000、#cc0000 等。在 if/else 条件中添加所有异常也不实际,有什么快速的想法吗?
最佳答案
将 HTML 颜色转换为 RGB,然后转换为 Hue-Saturation-Lightnes (HSV)
<?php
function HTMLToRGB($htmlCode)
{
if($htmlCode[0] == '#')
$htmlCode = substr($htmlCode, 1);
if (strlen($htmlCode) == 3)
{
$htmlCode = $htmlCode[0] . $htmlCode[0] . $htmlCode[1] . $htmlCode[1] . $htmlCode[2] . $htmlCode[2];
}
$r = hexdec($htmlCode[0] . $htmlCode[1]);
$g = hexdec($htmlCode[2] . $htmlCode[3]);
$b = hexdec($htmlCode[4] . $htmlCode[5]);
return $b + ($g << 0x8) + ($r << 0x10);
}
function RGBToHSL($RGB) {
$r = 0xFF & ($RGB >> 0x10);
$g = 0xFF & ($RGB >> 0x8);
$b = 0xFF & $RGB;
$r = ((float)$r) / 255.0;
$g = ((float)$g) / 255.0;
$b = ((float)$b) / 255.0;
$maxC = max($r, $g, $b);
$minC = min($r, $g, $b);
$l = ($maxC + $minC) / 2.0;
if($maxC == $minC)
{
$s = 0;
$h = 0;
}
else
{
if($l < .5)
{
$s = ($maxC - $minC) / ($maxC + $minC);
}
else
{
$s = ($maxC - $minC) / (2.0 - $maxC - $minC);
}
if($r == $maxC)
$h = ($g - $b) / ($maxC - $minC);
if($g == $maxC)
$h = 2.0 + ($b - $r) / ($maxC - $minC);
if($b == $maxC)
$h = 4.0 + ($r - $g) / ($maxC - $minC);
$h = $h / 6.0;
}
$h = (int)round(255.0 * $h);
$s = (int)round(255.0 * $s);
$l = (int)round(255.0 * $l);
return (object) Array('hue' => $h, 'saturation' => $s, 'lightness' => $l);
}
$colour = '#F12346';
$rgb = HTMLToRGB($colour);
$hsl = RGBToHSL($rgb);
var_dump($hsl);
用法:
$colour = '#F12346';
$rgb = HTMLToRGB($colour);
$hsl = RGBToHSL($rgb);
if($hsl->lightness > 200) {
// this is light colour!
}
来源:
演示:
关于php - 如何使用 PHP 检测 "light"颜色,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12228644/