c - 我如何获得C中目录的大小？

Question

是否有一个 POSIX 函数可以给出目录(包括所有子文件夹)的大小，大致相当于“du -s somepath”？

Answer 1

$ man nftw

NAME

ftw, nftw - file tree walk

DESCRIPTION

ftw() walks through the directory tree that is located under the directory dirpath, and calls fn() once for each entry in the tree. By default, directories are handled before the files and subdirectories they contain (pre-order traversal).

CONFORMING TO

POSIX.1-2001, SVr4, SUSv1.

简单例子

#include <stdio.h>
#include <errno.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/stat.h>

static unsigned int total = 0;

int sum(const char *fpath, const struct stat *sb, int typeflag) {
    total += sb->st_size;
    return 0;
}

int main(int argc, char **argv) {
    if (!argv[1] || access(argv[1], R_OK)) {
        return 1;
    }
    if (ftw(argv[1], &sum, 1)) {
        perror("ftw");
        return 2;
    }
    printf("%s: %u\n", argv[1], total);
    return 0;
}