<分区>
我有一个 SQLite 数据库,正在尝试使用 PHP 连接到它。这是我正在使用的:
<?php
$dbconn = sqlite_open('combadd.sqlite');
if ($dbconn) {
$result = sqlite_query($dbconn, "SELECT * FROM combo_calcs WHERE options='easy'");
var_dump(sqlite_fetch_array($result, SQLITE_ASSOC));
} else {
print "Connection to database failed!\n";
}
?>
但是,我得到这个错误:
Warning:
sqlite_open()
[function.sqlite-open]: file is encrypted or is not a database inC:\xampp\htdocs\deepthi\combadd\combadd_db.php
on line 4
Connection to database failed!
出了什么问题,我该如何解决?