PHP电子邮件表单发件人名称而不是电子邮件?

标签 php html css

现在,我已经设置了一个 PHP 电子邮件表单并且一切正常。但是,在测试时,我只得到发件人电子邮件地址作为名称。我想要的是发件人的姓名,例如:

李四

主题主题主题

代替:

j.doe@website.com

主题主题主题

下面是代码...

有人可以帮帮我吗?谢谢。

PHP:

<?php
if(isset($_POST['email'])) {

    // EDIT THE 2 LINES BELOW AS REQUIRED
    $email_to = "ricky@rickytsang.ca";
    $email_subject = $_REQUEST['subject'];


    function died($error) {
        // your error code can go here
        echo "We are very sorry, but there were error(s) found with the form you submitted. ";
        echo "These errors appear below.<br /><br />";
        echo $error."<br /><br />";
        echo "Please go back and fix these errors.<br /><br />";
        die();
    }

    // validation expected data exists
    if(!isset($_POST['full_name']) ||
        !isset($_POST['email']) ||
        !isset($_POST['subject']) ||
        !isset($_POST['message'])) {
        died('We are sorry, but there appears to be a problem with the form you submitted.');      
    }

    $full_name = $_POST['full_name']; // required
    $email_from = $_POST['email']; // required
    $subject = $_POST['subject'];
    $message= $_POST['message']; // required

    $error_message = "";
    $email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/';
  if(!preg_match($email_exp,$email_from)) {
    $error_message .= 'The e-mail you entered does not appear to be valid.<br />';
  }
    $string_exp = "/^[A-Za-z .'-]+$/";
  if(!preg_match($string_exp,$full_name)) {
    $error_message .= 'The name you entered does not appear to be valid.<br />';
  }
  if(strlen($message) < 2) {
    $error_message .= 'The message you entered doee not appear to be valid.<br />';
  }
  if(strlen($error_message) > 0) {
    died($error_message);
  }
    $email_message = "Form details below.\n\n";

    function clean_string($string) {
      $bad = array("content-type","bcc:","to:","cc:","href");
      return str_replace($bad,"",$string);
    }

    $email_message .= "Full Name: ".clean_string($full_name)."\n";
    $email_message .= "E-mail: ".clean_string($email_from)."\n";
    $email_message .= "Subject: ".clean_string($subject)."\n";
    $email_message .= "Message: ".clean_string($message)."\n";


// create email headers
$headers = 'From: '.$email_from."\r\n".
'Reply-To: '.$email_from."\r\n" .
'X-Mailer: PHP/' . phpversion();
@mail($email_to, $email_subject, $email_message, $headers); 
?>

<!-- include your own success html here -->

Thank you for contacting us. We will be in touch with you very soon.

<?php
}
?>

最佳答案

在您的 4 行 $email_message .= ... 之后添加一行:

$email_from = $full_name.'<'.$email_from.'>';

关于PHP电子邮件表单发件人名称而不是电子邮件?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6728361/

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