c - 如何修复 C 中的 "incompatible pointer type"错误？

Question

我有关于函数指针和在 C 中实现继承的作业。我收到关于 Aralik、VerilenlerArasindan 和 Harfler 的“指针类型不兼容”错误。有什么问题吗？

RastgeleKarakter.h

    struct RASTGELEKARAKTER{
        Random ran;
        char (*Harf)(struct RASTGELEKARAKTER*);
        char* (*Harfler)(struct RASTGELEKARAKTER*);
        char* (*Aralik)(struct RASTGELEKARAKTER*);
        char* (*VerilenlerArasindan)(struct RASTGELEKARAKTER*);
        char* (*Cumle)(struct RASTGELEKARAKTER*);
        void (*YokEt)(struct RASTGELEKARAKTER*);
    };

    typedef struct RASTGELEKARAKTER* RastgeleKarakter;

    RastgeleKarakter RastegeleKarakterOlustur();
    char RandomHarf(RastgeleKarakter);
    char* RandomHarfler(RastgeleKarakter,unsigned);
    char* RandomAralik(RastgeleKarakter,unsigned,char,char);
    char* RandomVerilenlerArasindan(RastgeleKarakter,unsigned,char*);
    char* RandomCumle(RastgeleKarakter);
    void RastgeleKarakterYokEt(RastgeleKarakter);

RastgeleKarakter.c

RastgeleKarakter RastegeleKarakterOlustur(){

    RastgeleKarakter karakter;
    karakter = (RastgeleKarakter)malloc(sizeof(struct RASTGELEKARAKTER));
    karakter->ran = RandomOlustur();
    karakter->Harf = &RandomHarf;
    karakter->Harfler = &RandomHarfler;
    karakter->Aralik = &RandomAralik;
    karakter->VerilenlerArasindan = &RandomVerilenlerArasindan;
    karakter->Cumle = &RandomCumle;
    karakter->YokEt = &RastgeleKarakterYokEt;
    return karakter;
}

Answer 1

warning: assignment from incompatible pointer type [-Wincompatible-pointer-types] karakter->Harfler = &RandomHarfler;

因为

char* (Harfler)(struct RASTGELEKARAKTER);

但是

char* RandomHarfler(RastgeleKarakter,unsigned);

RandomHarfler 获取两个参数，但 Harfler 必须接收指向函数的指针，该函数仅获取 struct RASTGELEKARAKTER*

---

warning: assignment from incompatible pointer type [-Wincompatible-pointer-types] karakter->Aralik = &RandomAralik;

因为

char* (Aralik)(struct RASTGELEKARAKTER);

但是

char* RandomAralik(RastgeleKarakter,unsigned,char,char);

RandomAralik 获取 4 个参数，但 Aralik 必须接收指向函数的指针，该函数仅获取 struct RASTGELEKARAKTER*

---

warning: assignment from incompatible pointer type [-Wincompatible-pointer-types] karakter->VerilenlerArasindan = &RandomVerilenlerArasindan;

因为

char* (VerilenlerArasindan)(struct RASTGELEKARAKTER);

但是

char* RandomVerilenlerArasindan(RastgeleKarakter,unsigned,char*);

RandomVerilenlerArasindan 获取 3 个参数，但 VerilenlerArasindan 必须接收指向仅获取 struct RASTGELEKARAKTER*

的函数的指针