我需要查明,ip 是否属于 ip 掩码。 例如:
ip = 192.168.0.1 掩码 = 192.168.0.1/24。
我找到了将 ip 转换为掩码的函数:
inet_cidrtoaddr(int cidr, struct in_addr *addr)
{
int ocets;
if (cidr < 0 || cidr > 32) {
errno = EINVAL;
return -1;
}
ocets = (cidr + 7) / 8;
addr->s_addr = 0;
if (ocets > 0) {
memset(&addr->s_addr, 255, (size_t)ocets - 1);
memset((unsigned char *)&addr->s_addr + (ocets - 1),
(256 - (1 << (32 - cidr) % 8)), 1);
}
return 0;
}
如何比较 ip 和 cidr 范围?
最佳答案
因此,将 Olis 的答案放入代码中:
// Check if 192.168.0.1 is inside 192.168.0.0/24
in_addr ip, net, netmask;
inet_aton("192.168.0.1", &ip);
inet_aton("192.168.0.0", &net);
他说:
inet_cidrtoaddr(24, &netmask);
bool is_inside = ((ip.s_addr & netmask.s_addr) == (net.s_addr & netmask.s_addr));
我更喜欢 addr4_match方法虽然:
bool cidr_match(const in_addr &addr, const in_addr &net, uint8_t bits) {
if (bits == 0) {
// C99 6.5.7 (3): u32 << 32 is undefined behaviour
return true;
}
return !((addr.s_addr ^ net.s_addr) & htonl(0xFFFFFFFFu << (32 - bits)));
}
bool is_inside = cidr_match(ip, net, 24);
我尝试了一堆不同的输入:https://gist.github.com/duedal/b83303b4988a4afb2a75
如果有人发现这也需要 IPv6 解决方案:
bool cidr6_match(const in6_addr &address, const in6_addr &network, uint8_t bits) {
#ifdef LINUX
const uint32_t *a = address.s6_addr32;
const uint32_t *n = network.s6_addr32;
#else
const uint32_t *a = address.__u6_addr.__u6_addr32;
const uint32_t *n = network.__u6_addr.__u6_addr32;
#endif
int bits_whole, bits_incomplete;
bits_whole = bits >> 5; // number of whole u32
bits_incomplete = bits & 0x1F; // number of bits in incomplete u32
if (bits_whole) {
if (memcmp(a, n, bits_whole << 2)) {
return false;
}
}
if (bits_incomplete) {
uint32_t mask = htonl((0xFFFFFFFFu) << (32 - bits_incomplete));
if ((a[bits_whole] ^ n[bits_whole]) & mask) {
return false;
}
}
return true;
}
检查 2001:db8::ff00:42:8329 是否存在于 2001:db8/32 中。当心 inet_net_pton 非常挑剔,它是 2001:db8/32 而不是 2001:db8::/32。但是 2001:db8::/48 是完全有效的(也称为 2001:db8:0/48)。
in6_addr ip6, net6, net6_48;
memset(&net6, 0, sizeof(net6));
memset(&net6_48, 0, sizeof(net6_48));
assert(inet_pton(AF_INET6, "2001:db8::ff00:42:8329", &ip6));
int bits = inet_net_pton(AF_INET6, "2001:db8/32", &net6, sizeof(net6));
assert((bits != -1)); // assert that inet_net_pton understood us
bool is_inside6 = cidr6_match(ip6, net6, bits);
int bits_48 = inet_net_pton(AF_INET6, "2001:db8::/48", &net6_48, sizeof(net6_48));
assert((bits_48 == 48));
bool is_inside6_48 = cidr6_match(ip6, net6_48, bits_48);
关于c - IP cidr匹配功能,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7213995/