c - 警告 C4047 : '=' : 'char' differs in levels of indirection from 'char *'

Question

下面显示的代码有什么问题。

char filter[2] = {'\0'};
*filter = (char *)calloc((unsigned int)buf.st_size + 1, sizeof(unsigned char));

据我了解，改变数组位置没有问题吧？为什么我问这个是因为警告，

Warning 1   warning C4047: '=' : 'char' differs in levels of indirection from 'char *'

有什么想法吗？

明白了，把代码改成。谢谢@ouah

char *filter = {'\0'};
filter = (char *)calloc((unsigned int)buf.st_size + 1, sizeof(unsigned char));

Answer 1

*filter 是一个 char，您正在为其分配一个 char * 值。