c - strtok_r 导致 "assignment makes pointer from integer without a cast"

Question

我正在尝试在 C 中对字符串进行标记化，并使用 strtok_r 将标记保存到多个变量中。据我所知，我完全按照记录使用它:

char *saveptr;

char *ticketuser = strtok_r(request, ":", &saveptr);
char *ticketservice = strtok_r(NULL, ":", &saveptr);
char *ticketkey = strtok_r(NULL, ":", &saveptr);
//And so on...

其中“请求”是一串以冒号分隔的标记。当我尝试编译时，我在分配其中一个字符串的每一行上都得到“赋值从整数生成指针而不进行强制转换”。由于 strtok_r 应该返回一个 char*，我看不出问题出在哪里。

编辑:这是我所有的代码:

#include <stdio.h>

char *add( char *request ) {

  char *name = "add";
  char *secret = "secret1";
  char *failcode = "0:add:0";
  char returncode[80];
  char *saveptr;

  char *username = strtok_r(request, ":", &saveptr);
  char *servicename = strtok_r(NULL, ":", &saveptr);
  int parameter1 = atoi(strtok_r(NULL, ":", &saveptr));
  int parameter2 = atoi(strtok_r(NULL, ":", &saveptr));
  int ticketlead1 = atoi(strtok_r(NULL, ":", &saveptr));
  char *ticketuser = strtok_r(NULL, ":", &saveptr);
  char *ticketservice = strtok_r(NULL, ":", &saveptr);
  char *ticketkey = strtok_r(NULL, ":", &saveptr);

  //Catch any issues with the request
  if (strcmp(username,ticketuser) != 0){
    printf("username did not match ticket username\n");
    return failcode;
  }//if
  else if (strcmp(servicename,ticketservice) != 0){
    printf("service name did not match ticket service name\n");
    return failcode;
  }//else if
  else if (strcmp(secret,ticketkey) != 0){
    printf("secret key did not match ticket secret key\n");
    return failcode;
  }//else if

  //request was good, return value
  else{
    int val = parameter1 + parameter2;
    sprintf(returncode, "1:add:%d", val);
    return returncode;
  }//else

}//add


int main( int argc, char **argv ) {

  char *returned;
  char *req = "user:serv:5:8:1:user:serv:secret1";
  returned  = add(req);

  printf(returned);
  printf("\n");

  return 1;

}//main

Answer 1

答案在评论中找到:我失踪了#include <string.h>在文件的顶部。

编辑:我应该补充一点，除了上述问题之外，还有其他问题。首先，saveptr应该初始化为空。其次，正如 BLUEPIXY 指出的那样，returncode[]是局部变量。将其定义替换为 char *returncode = malloc ( . . . );