php - 计算PHP中两个日期之间的年数

Question

我需要从提供的 2 个日期中获取年数。这是我的代码:

function daysDifference($endDate, $beginDate)
{
   $date_parts1=explode("-", $beginDate);
   $date_parts2=explode("-", $endDate);

   $start_date=gregoriantojd($date_parts1[1], $date_parts1[2], $date_parts1[0]);
   $end_date=gregoriantojd($date_parts2[1], $date_parts2[2], $date_parts2[0]);
   $diff = $end_date - $start_date;
   echo $diff;
   $years = floor($diff / (365.25*60*60*24));
   return $years;
}

echo daysDifference('2011-03-12','2008-03-09');

$diff 给出一个数字输出。当我返回 $years 时，我得到了 0。我做错了什么？

Answer 1

$d1 = new DateTime('2011-03-12');
$d2 = new DateTime('2008-03-09');

$diff = $d2->diff($d1);

echo $diff->y;