git - 调整脚本以 pull 所有远程分支

标签 git

我已经开始使用另一个 thread 中发布的一个脚本:

#!/bin/bash

main() {
  REMOTES="$@";
  if [ -z "$REMOTES" ]; then
    REMOTES=$(git remote);
  fi
  REMOTES=$(echo "$REMOTES" | xargs -n1 echo)
  CLB=$(git branch -l|awk '/^\*/{print $2}');
  echo "$REMOTES" | while read REMOTE; do
    git remote update $REMOTE
    git remote show $REMOTE -n \
    | awk '/merges with remote/{print $5" "$1}' \
    | while read line; do
      RB=$(echo "$line"|cut -f1 -d" ");
      ARB="refs/remotes/$REMOTE/$RB";
      LB=$(echo "$line"|cut -f2 -d" ");
      ALB="refs/heads/$LB";
      NBEHIND=$(( $(git rev-list --count $ALB..$ARB 2>/dev/null) +0));
      NAHEAD=$(( $(git rev-list --count $ARB..$ALB 2>/dev/null) +0));
      if [ "$NBEHIND" -gt 0 ]; then
        if [ "$NAHEAD" -gt 0 ]; then
          echo " branch $LB is $NBEHIND commit(s) behind and $NAHEAD commit(s) ahead of $REMOTE/$RB. could not be fast-forwarded";
        elif [ "$LB" = "$CLB" ]; then
          echo " branch $LB was $NBEHIND commit(s) behind of $REMOTE/$RB. fast-forward merge";
          git merge -q $ARB;
        else
          echo " branch $LB was $NBEHIND commit(s) behind of $REMOTE/$RB. reseting local branch to remote";
          git branch -l -f $LB -t $ARB >/dev/null;
        fi
      fi
    done
  done
}

main $@

到目前为止效果很好,但我想知道如何调整它以 pull 所有分支,由于某种原因它不会 pull 某些本地分支。

第一个例子:我有 4 个本地分支落后,master 是当前分支,在运行这个脚本后,一些相对于远程落后的分支 (4) 被 pull 出,但我仍然可以看到 Remote 后面的 master 分支如下图:

enter image description here

第二个例子:在运行脚本之前,我得到了这个,后面有 2 个本地分支,当前的分支(发布)没问题:

enter image description here

我运行脚本并得到了这个:

enter image description here

那么,我如何调整脚本以 pull “所有”本地分支?

最佳答案

另外to my previous answer ,我想补充一点,你的脚本应该只将给定分支的 merge 或重置限制到它的上游分支。
因此我使用了 %(upstream:track)

这是我刚刚测试过的脚本:

  • git 版本 2.11.0.windows.1
  • SourceTree 1.9.10.0

即:

#!/bin/bash

branches=$(git for-each-ref --format="%(refname) %(upstream) %(upstream:track)" refs/heads)

echo "${branches}"
branch_checkedout=$(cat .git/HEAD|cut -f2 -d" ")
echo branch checked out: "${branch_checkedout}"

while read -r branch_line; do
  ahead=0
  behind=0
  branch_local=$(echo ${branch_line}|cut -f1 -d" ")
  branch_remote=$(echo ${branch_line}|cut -f2 -d" ")
  echo ${branch_line} | grep "ahead" >/dev/null && ahead=1
  echo ${branch_line} | grep "behind" >/dev/null && behind=1
  NAHEAD=$(( $(git rev-list --count ${branch_remote}..${branch_local} 2>/dev/null) +0))
  NBEHIND=$(( $(git rev-list --count ${branch_local}..${branch_remote} 2>/dev/null) +0));

  if [ "$NBEHIND" -gt 0 ]; then
    if [ "$NAHEAD" -gt 0 ]; then
      echo " branch $LB is $NBEHIND commit(s) behind and $NAHEAD commit(s) ahead of $REMOTE/$RB. could not be fast-forwarded";
    elif [ "${branch_local}" = "${branch_checkedout}" ]; then
      echo " branch ${branch_local} was $NBEHIND commit(s) behind of ${branch_remote}. fast-forward merge";
      echo "git merge -q ${branch_remote}"
      git merge -q ${branch_remote};
    else
      echo " branch ${branch_local} was $NBEHIND commit(s) behind of ${branch_remote}. reseting local branch to remote";
      bl=${branch_local#*/}
      bl=${bl#*/}
      echo "git branch -l -f ${bl} -t ${branch_remote}"
      git branch -l -f ${bl} -t ${branch_remote} >/dev/null;
    fi
  fi
done <<< "${branches}"

注意使用:

  • branches=$(git for-each-ref --format="%(refname) %(upstream) %(upstream:track)"refs/heads)
    获取完整的上游分支名称和领先/落后状态
  • branch_checkedout=$(cat .git/HEAD|cut -f2 -d"") 获取 check out 分支的名称
  • while read -r branch_line;做 只在有上游的分支上循环,而不是“所有的远程”(可能包括也可能不包括给定的分支)

关于git - 调整脚本以 pull 所有远程分支,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40490856/

相关文章:

git - AWS Codecommit Git 克隆错误 : fatal: unable to find remote helper for 'codecommit'

git - 在 Windows 7 上使用 git 的 GitHub 的 https 证书错误

Android Studio - 基于 Git 的多平台项目的 CRLF 与 LF

git - 如何有效地审查 git 子模块更新/ rebase ?

git - 在 Visual Studio Code 中禁用推送选项

git - 通过 http(s) 克隆 git bundle

git - 关于 Git 的 merge 和 rebase

git - Git 比 SVN 需要更多空间吗?

git - 我有点与“源代码树”解决方案混淆: Resolve Using Mine and Resolve Using Theirs [duplicate]

git - 使用 git stash show 显示消息和差异