linux - Bash Linux Curl 从变量发送 header

Question

我有一些 bash 脚本。 我想用一些 header (cloudflare block :) 向服务器发送请求。

我是这样写的:

headers="\
-H 'Host: somesite.com' \
-H 'Accept-Language: pl,en-US;q=0.7,en;q=0.3' \
-H 'Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8' \
-H 'User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:32.0) Gecko/20100101 Firefox/32.0' \
-H 'Accept-Encoding: gzip, deflate' \
-H 'DNT: 1' \
-H 'Connection: keep-alive'";

curl $headers somesite.com

但在输出中我有这个..

curl: (6) Couldn't resolve host 'Accept-Language'
curl: (6) Couldn't resolve host 'pl,en-US;q=0.7,en;q=0.3'
curl: (6) Couldn't resolve host 'Accept'
curl: (6) Couldn't resolve host 'text'
curl: (6) Couldn't resolve host 'User-Agent'
curl: (6) Couldn't resolve host 'Mozilla'
curl: (6) Couldn't resolve host '(Windows'
curl: (6) Couldn't resolve host 'NT'
curl: (6) Couldn't resolve host '6.1;'

如何将标题从变量放入命令？

Answer 1

不要为此使用字符串。尝试在这样的字符串中正确引用基本上是不可能的，请使用数组。

参见 http://mywiki.wooledge.org/BashFAQ/050了解更多。