linux - bash 中的 "syntax error near unexpected token ` elif '"错误

Question

我写了一个脚本，部分脚本如下:

#!/bin/bash

if [ "$1" == "this_script" ] then
      this_script --parameters
elif [ "$1" == "other_script" ] then
      other_script --parameters
else
      echo "missing argument"
fi

当我运行这个脚本时，我得到了错误，

syntax error near unexpected token `elif'
`elif [ "$1" == "SWDB" ] then'

1) 行尾有问题吗？我在 Windows 上用 Notepad++ 编写了脚本，但我在编辑到 UNIX/OSX 格式下启用了 EOL 转换。

2) 如果不是行尾，错误是什么？

我在 Redhat Linux 操作系统的 bash shell 中运行这个脚本。

Answer 1

在 if [ ... ] 之后和 then 之前需要一个分号，对于 elif 也是如此:

if [ "$1" == "this_script" ]; then
#                           ^
#                           here!
#                              v
elif [ "$1" == "other_script" ]; then

来自 Bash manual - 3.2.4.2 Conditional Constructs :

The syntax of the if command is:

if test-commands; then
  consequent-commands;
[elif more-test-commands; then
  more-consequents;]
[else alternate-consequents;]
fi

The test-commands list is executed, and if its return status is zero, the consequent-commands list is executed. If test-commands returns a non-zero status, each elif list is executed in turn, and if its exit status is zero, the corresponding more-consequents is executed and the command completes. If ‘else alternate-consequents’ is present, and the final command in the final if or elif clause has a non-zero exit status, then alternate-consequents is executed. The return status is the exit status of the last command executed, or zero if no condition tested true.