我从这里得到一段 Python 代码: http://www.raspberry-pi-geek.com/Archive/2013/01/Adding-an-On-Off-switch-to-your-Raspberry-Pi
我想改进它。
因为这是我第一次使用 Python,所以我一直在理解实际发生的事情。
代码如下:
# Import the modules to send commands to the system and access GPIO pins
from subprocess import call
import RPi.GPIO as gpio
from time import sleep
gpio.setmode(gpio.BCM) # Set pin numbering to board numbering
gpio.setup(22, gpio.IN) # Set up pin 22 as an input
rebootBool = 0
# Define a function to keep script running
def main(pin):
while True:
#gpio.remove_event_detect(pin)
gpio.add_event_detect(22, gpio.RISING, callback=confirmation, bouncetime=200) # Set up an interrupt to look for button presses
sleep(5000000)
def confirmation(pin):
gpio.remove_event_detect(pin)
gpio.add_event_detect(22, gpio.RISING, callback=shutdown, bouncetime=200)
sleep(3) # if button has been pressed again within 3 seconds, shut down will happen
main(22)
def reboot(pin):
rebootBool = 1
call('reboot', shell=False)
exit(0)
# Define a function to run when an interrupt is called
def shutdown(pin):
gpio.remove_event_detect(pin)
gpio.add_event_detect(22, gpio.RISING, callback=reboot, bouncetime=200)
sleep(3) # if the button has been pressed for a third time, within 3 seconds, Pi will reboot
if rebootBool == 0: # Just to make sure a halt is not called after the 3 seconds have passed, if reboot is called
call('halt', shell=False)
exit(0)
main(22) # Run the loop function to keep script running
我想做的是:
- 如果按下按钮一次,则执行确认功能,如果在 3 秒内按下按钮,它会重置按钮以调用关机功能。
- 否则,继续主循环
- 在关机功能中,如果再次按下(3 秒内),它会重置以调用重启功能。
- 否则继续,关闭
这是怎么回事:
如果我按按钮两次或三次,它会告诉我 gpio.add_event_detect 已经定义,当它试图在 main() 中定义它时。 所以它不会改变它,如果我再按一次,它会调用关机功能。
我不明白的是:
为什么它要在 main 中定义 gpio 事件,而实际功能是重启或关机(它应该调用重启或关机)?
最佳答案
因为一个回调函数是在一个单独的线程中运行的。这意味着,例如,当您在主循环中调用任何回调函数时它仍然有效(主循环),因此当您从回调函数(线程#1)和主循环中调用函数 gpio.add_event_detect 时会发生这种情况(线程#2)同时。这是典型的比赛条件。 您可以通过运行此代码来检查它:
#!/usr/bin/python
# Import the modules to send commands to the system and access GPIO pins
from subprocess import call
import RPi.GPIO as gpio
from time import sleep
gpio.setmode(gpio.BCM) # Set pin numbering to board numbering
gpio.setup(22, gpio.IN, pull_up_down=gpio.PUD_DOWN) # Set up pin 22 as an input
rebootBool = 0
# Define a function to keep script running
def main(pin):
while True:
print "main loop"
gpio.remove_event_detect(22)
gpio.add_event_detect(22, gpio.RISING, callback=confirmation, bouncetime=200) # Set up an interrupt to look for button presses
sleep(1)
#raw_input()
def confirmation(pin):
print "confirmation1"
sleep(5)
print "confirmation2"
gpio.remove_event_detect(22)
gpio.add_event_detect(22, gpio.RISING, callback=shutdown, bouncetime=200)
sleep(5) # if button has been pressed again within 3 seconds, shut down will happen
gpio.remove_event_detect(22)
main(22)
def reboot(pin):
rebootBool = 1
print "reboot"
#call('reboot', shell=False)
exit(0)
# Define a function to run when an interrupt is called
def shutdown(pin):
print "shutdown"
gpio.remove_event_detect(pin)
gpio.add_event_detect(22, gpio.RISING, callback=reboot, bouncetime=200)
sleep(3) # if the button has been pressed for a third time, within 3 seconds, Pi will reboot
if rebootBool == 0: # Just to make sure a halt is not called after the 3 seconds have passed, if reboot is called
#call('halt', shell=False)
print "halt"
exit(0)
main(22) # Run the loop function to keep script running
关于Python "shutdown/reboot raspberry pi"脚本,使用单个按钮,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30334424/