java - Android 从 Sqlite 数据库中保存并获取图像

Question

亲爱的 我如何使用 Android Studio 保存图像并从 Sqlite 数据库获取图像？

Answer 1

可能为时已晚。但对 future 的读者有用..

import android.content.Context;
import android.database.Cursor;
import android.database.DatabaseUtils;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;
import android.database.sqlite.SQLiteStatement;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;


import java.util.HashMap;

 /**
  * Created by Noorul on 23-05-2016.
 */

@SuppressWarnings("ALL")
public class DBSplash extends SQLiteOpenHelper {

public static final String DATABASE_NAME = "SplashDB.db";
public static final String SPLASH_TABLE_NAME = "splash_db";

private HashMap hp;

public DBSplash(Context context) {
    super(context, DATABASE_NAME, null, 1);
}

@Override
public void onCreate(SQLiteDatabase db) {
    db.execSQL(
            "create table " + SPLASH_TABLE_NAME + "( name TEXT, image BLOB)"
    );
}

@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
    // TODO Auto-generated method stub
    db.execSQL("DROP TABLE IF EXISTS contacts");
    onCreate(db);
}

public boolean insertImage(String name, Bitmap img) {
    Bitmap storedBitmap = null;
    String sql = "INSERT INTO " + SPLASH_TABLE_NAME + " (name,image) VALUES(?,?)";
    SQLiteDatabase db = this.getWritableDatabase();
    SQLiteStatement insertStmt = db.compileStatement(sql);

    byte[] imgByte = getBitmapAsByteArray(img);
    try {
        storedBitmap = getImage(name);
    } catch (Exception e) {
        AppLog.exception(e);
    }
    if (storedBitmap == null) {
        insertStmt.bindString(1, name);
        insertStmt.bindBlob(2, imgByte);
        insertStmt.executeInsert();
        db.close();
    }
    return true;
}


public int numberOfRows() {
    SQLiteDatabase db = this.getReadableDatabase();
    int numRows = (int) DatabaseUtils.queryNumEntries(db, SPLASH_TABLE_NAME);
    return numRows;
}


public Bitmap getImage(String name) {
    String qu = "SELECT * FROM " + SPLASH_TABLE_NAME;
    Cursor cur = null;
    SQLiteDatabase db = this.getReadableDatabase();

    try {
        cur = db.rawQuery(qu, new String[]{});
    } catch (Exception e) {
        AppLog.exception(e);
    }
    if (cur != null) {
        if (cur.moveToFirst()) {
            int index = cur.getColumnIndexOrThrow("image");
            byte[] imgByte = cur.getBlob(index);
            cur.close();
            return BitmapFactory.decodeByteArray(imgByte, 0, imgByte.length);
        }
        if (cur != null && !cur.isClosed()) {
            cur.close();
        }
    }

    return null;
}
   public byte[] getBitmapAsByteArray(Bitmap bitmap) {
    ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
    bitmap.compress(Bitmap.CompressFormat.JPEG, 0, outputStream);
    return outputStream.toByteArray();
}
}

使用此代码。但是将图像存储在数据库中并不是最佳做法。如果您需要清晰的图像，请更改图像大小。图像是具有高内存的 blob 类型。手机是更小的设备。所以在 sqlite db 中存储许多图像意味着，它会很难看。所以使用@thuongle 方法