Java Android 将数据发送到服务器应用程序永远不要使用 onPostExecute()

Question

我在向服务器发送数据时遇到问题，为了与服务器连接，我使用了套接字。为了将数据发送到服务器，我使用 AsyncTask。我有一个问题:

当应用程序发送数据时，我的应用程序看不到完成此操作，它从不使用onPostExecute()。

这是我的代码:

public class MyClientTask extends AsyncTask<Void, Void, Void> {
        String dstAddress;
        int dstPort;
        String response = "";

        MyClientTask(String addr, int port) {
            dstAddress = addr;
            dstPort = port;
        }

        @Override
        protected Void doInBackground(Void... arg0) {
//            if (pingHost(1000)) {
            socket = null;
            try {
                socket = new Socket(dstAddress, dstPort);
                ByteArrayOutputStream byteArrayOutputStream =
                        new ByteArrayOutputStream(1024);
                byte[] buffer = new byte[1024];
                DataOutputStream outputStream = new DataOutputStream(socket.getOutputStream());

                byte[] theByteArray = message.getBytes();
                lengthMessage = (short) theByteArray.length;

                outputStream.writeByte((byte) 0xB);
                outputStream.writeByte((byte) 0xA);
                outputStream.writeByte((byte) 0xA);
                outputStream.writeByte((byte) 0xD);
                outputStream.writeShort(lengthMessage);
                outputStream.write(theByteArray);
                outputStream.writeShort(width);
                outputStream.writeShort(height);
                outputStream.writeInt(lengthbmp);
                outputStream.writeInt(lengthResizebmp);
                outputStream.writeShort(11);
                outputStream.write(imageInByte );
                outputStream.write(imageResizeInByte);
                outputStream.writeByte((byte) 0xB);
                outputStream.writeByte((byte) 0xE);
                outputStream.writeByte((byte) 0xE);
                outputStream.writeByte((byte) 0xF);

                try {
                    Thread.sleep(2000);
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }


                int bytesRead;
                InputStream inputStream = socket.getInputStream();

                while ((bytesRead = inputStream.read(buffer)) != -1) {
                    byteArrayOutputStream.write(buffer, 0, bytesRead);
                    response += byteArrayOutputStream.toString("UTF-8");
                }

                outputStream.flush();
                outputStream.close();

            } catch (UnknownHostException e) {
                e.printStackTrace();
                isSuccsess = false;
                response = "UnknownHostException: " + e.toString();
            } catch (IOException e) {
                e.printStackTrace();
                Log.d("la", "nie udało sie");
                isSuccsess = false;
                response = "IOException: " + e.toString();
            }
            return null;
        }

        @Override
        protected void onPostExecute(Void result) {
            super.onPostExecute(result);
            if (socket != null) {
                try {
                    socket.shutdownInput();
                    socket.shutdownOutput();
                    socket.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            if(isSuccsess){
                Toast.makeText(MainActivity.this, "Zdjęcie zostało wysłane !" , Toast.LENGTH_LONG).show();
                bm = null;
                clearEt();
                ivImage.setImageBitmap(bm);
            }
            else{
                Toast.makeText(MainActivity.this , "Nie udało się wysłać zdjęcia !" , Toast.LENGTH_LONG).show();
            }

            pbWheel.setVisibility(View.INVISIBLE);
        }

        @Override
        protected void onPreExecute() {
            super.onPreExecute();
            pbWheel.setVisibility(View.VISIBLE);
        }
    }

Answer 1

您可以使用AsyncTask<Void,Void,Integer> ，并在 doInBackground 中返回任何整数而不是 null。

只需替换(在 doInBackground 中)

return null;

与

return 1;

并替换(在 AsyncTask 声明中)

public class MyClientTask extends AsyncTask<Void, Void, Void> {

与

public class MyClientTask extends AsyncTask<Void, Void, Integer> {