I have one url with request parameter is in JsonFormat like {"EmailAddress":"[email protected]","PassWord":"password"} it's requested parameter. When i used in POSTMAN then its okey.but when i request with program then that time i got error response. ihave tried till like this please see this snippet.
public class LoginModel {
@SerializedName("EmailAddress")
public String userName;
@SerializedName("PassWord")
public String userPass;
}
@Override
public String toString() {
Log.e("POSTLOGIN_MODEL" , userName+"||"+userPass);
return "{" +
"EmailAddress='" + userName + '\'' +
", PassWord='" + userPass + '\'' +
'}';
}
}
After that i used Interface.
public interface ApiService {
@FormUrlEncoded
@POST("/json/syncreply/AuthenticateUserRequest?")
Call<LoginResponse> LoginService(@Field("EmailAddress") String userName, @Field("PassWord") String userPass, Callback<LoginResponse> callBack);
After that i used to call this interface method through activity.
login.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if(input_username.getText().toString() != null && input_password.getText().toString() != null
&& !input_username.getText().toString().isEmpty() && !input_password.getText().toString().isEmpty()){
LoginModel loginCredentials = new LoginModel();
loginCredentials.userName = "<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="017564727541666c60686d2f626e6c" rel="noreferrer noopener nofollow">[email protected]</a>";
loginCredentials.userPass = "password";
String request = "{\"EmailAddress\":\"<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="f2809398b2959f939b9edc919d9f" rel="noreferrer noopener nofollow">[email protected]</a>\"," +
"\"PassWord\":\"pass\"}";
sendPost(loginCredentials);
}else{
Toast.makeText(getApplicationContext() , "Please enter valid Username and Password." , Toast.LENGTH_LONG).show();
}
}
});
public void sendPost(LoginModel name) {
Log.e("TAG","||"+name.userPass+"||"+name.userName);
// mAPIService.savePost(name).enqueue(new Callback<LoginModel>() {
Call<LoginResponse> call = mAPIService.LoginService(name.userName, name.userPass, new Callback<LoginResponse>() {
@Override
public void onResponse(Call<LoginResponse> call, Response<LoginResponse> response) {
Log.e("TAG" , "RESPONSE"+"||"+response.body());
}
@Override
public void onFailure(Call<LoginResponse> call, Throwable t) {
Log.e("TAG" , "FAILURE"+"||"+t.getMessage());
}
});
}
Thanks In Advance.any answer will appriciated.my english is please avoid it.
最佳答案
Hey Rajan 使用请求正文传递 Json
String request = "{\"EmailAddress\":\"<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="6517040f250208040c094b060a08" rel="noreferrer noopener nofollow">[email protected]</a>\"," + "\"PassWord\":\"pass\"}";
RequestBody body = RequestBody.create(okhttp3.MediaType.parse("application/json; charset=utf-8"),request);
@Headers("Content-Type: application/json; charset=utf-8")
@POST("/json/syncreply/AuthenticateUserRequest")
Call<ResponseBody> AuthenticateUserRequest(@Body RequestBody body);
aCall.enqueue(new Callback<ResponseBody>() {
@Override
public void onResponse(Call<ResponseBody> call, Response<ResponseBody> response) {
if (response.isSuccessful()) {
ResponseBody responseBody = response.body();
}
}
@Override
public void onFailure(Call<ResponseBody> call, Throwable t) {
}
});
关于java - 如何在Android POST方法中与body一起使用Retrofit？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/42992029/