我在此主题之前已经问过这个问题,请仔细阅读sql-print-many-word-between-every-columns-with-many-conditions
但是这个问题和上一个问题之间的区别是我想在许多俱乐部名称中创建一个集体球员或一组球员:
El Ahly
俱乐部名称有12
玩家我要拆分成3
teams
每team
有 4
玩家我要数多少team
每个俱乐部的名字里面
然后将它们放入不可变数字(组)4 8 16 32 64 128 256
基于 teams
的数量打印 **ANY WORD**
在使用 select full_name,club_name from players where y_of_birth=2000
过滤数据后,它们之间会出现类似的情况所需的输出应该是这样的:
更新:
+----+------+---------------------+
| full_name | club_name |
+--------------+------------------+
| Ahmed Sayed | El Ahly |
+--------------+------------------+
| Kareem Gaber | El Ahly |
+--------------+------------------+
| Maher Zein | El Ahly |
+--------------+------------------+
| Mohab Saeed | El Ahly |
+----+------+--+------------------+
| ahmed shawky | Petroget |
+--------------+------------------+
| shaker ali | Petroget |
+--------------+------------------+
| omar Saed | Petroget |
+--------------+------------------+
| moataz Gamal | Petroget |
+------+-------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| husein mazen | Cocorico |
+--------------+------------------+
| hassan maged | Cocorico |
+--------------+------------------+
| maged ahmoud | Cocorico |
+--------------+------------------+
| zakareya gad | Cocorico |
+--------------+------------------+
| Kamal saber | El Ahly |
+--------------+------------------+
| gamel kamel | El Ahly |
+--------------+------------------+
| omar galal | El Ahly |
+--------------+------------------+
| Kamal saber | El Ahly |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| khaled zein | Petroget |
+--------------+------------------+
| shady sameer | Petroget |
+--------------+------------------+
| wahed mahmoud| Petroget |
+--------------+------------------+
| samy shahen | Petroget |
+----+------+--+------------------+
| Mohamed gad | El Ahly |
+----+------+--+------------------+
| ehab zeyad | El Ahly |
+----+---------+------------------+
| moaz maged | El Ahly |
+--------------+------------------+
| mazen mahmod | El Ahly |
+--------------+------------------+
在这个例子中,有 2 groups of
**ANY WORD**
因为它是 6
group
并将它们放入8
在 4
中发现的不可变组或 8
或 16
或 32
或 64
或 128
或 256
数字...并且 2 **ANY WORD**
之间没有相邻或两个相邻的 club_name
示例:
4 个玩家作为一个玩家
如果 select full_name,club_name from players where y_of_birth=2000
之后的结果是 12
玩家的意思12 players
= 3 groups
因为每个组都有4
玩家下一步打印**ANY WORD**
在 3 个组之间 4 次(注意:**ANY WORD**
是这些组之一)所以输出将是这样的:
+----+------+---------------------+
| full_name | club_name |
+--------------+------------------+
| Ahmed Sayed | El Ahly |
+--------------+------------------+
| Kareem Gaber | El Ahly |
+--------------+------------------+
| Maher Zein | El Ahly |
+--------------+------------------+
| Mohab Saeed | El Ahly |
+----+------+--+------------------+
| ahmed shawky | Petroget |
+--------------+------------------+
| shaker ali | Petroget |
+--------------+------------------+
| omar Saed | Petroget |
+--------------+------------------+
| moataz Gamal | Petroget |
+------+-------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| Kamal saber | El Ahly |
+--------------+------------------+
| gamel kamel | El Ahly |
+--------------+------------------+
| omar galal | El Ahly |
+--------------+------------------+
| Kamal saber | El Ahly |
+--------------+------------------+
结论:
4 8 16 32 64 128 256
是不可变的组
group 4
应填写16
拥有 **ANY WORD**
的玩家他们之间没有类似的东西:
+----+------+---------------------+
| full_name | club_name |
+--------------+------------------+
| Ahmed Sayed | El Ahly |
+--------------+------------------+
| Kareem Gaber | El Ahly |
+--------------+------------------+
| Maher Zein | El Ahly |
+--------------+------------------+
| Mohab Saeed | El Ahly |
+----+------+--+------------------+
| ahmed shawky | Petroget |
+--------------+------------------+
| shaker ali | Petroget |
+--------------+------------------+
| omar Saed | Petroget |
+--------------+------------------+
| moataz Gamal | Petroget |
+------+-------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| Kamal saber | El Ahly |
+--------------+------------------+
| gamel kamel | El Ahly |
+--------------+------------------+
| omar galal | El Ahly |
+--------------+------------------+
| Kamal saber | El Ahly |
+--------------+------------------+
group 8
应填写32
拥有 **ANY WORD**
的玩家他们之间没有类似的东西:
+----+------+---------------------+
| full_name | club_name |
+--------------+------------------+
| Ahmed Sayed | El Ahly |
+--------------+------------------+
| Kareem Gaber | El Ahly |
+--------------+------------------+
| Maher Zein | El Ahly |
+--------------+------------------+
| Mohab Saeed | El Ahly |
+----+------+--+------------------+
| ahmed shawky | Petroget |
+--------------+------------------+
| shaker ali | Petroget |
+--------------+------------------+
| omar Saed | Petroget |
+--------------+------------------+
| moataz Gamal | Petroget |
+------+-------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| husein mazen | Cocorico |
+--------------+------------------+
| hassan maged | Cocorico |
+--------------+------------------+
| maged ahmoud | Cocorico |
+--------------+------------------+
| zakareya gad | Cocorico |
+--------------+------------------+
| Kamal saber | El Ahly |
+--------------+------------------+
| gamel kamel | El Ahly |
+--------------+------------------+
| omar galal | El Ahly |
+--------------+------------------+
| Kamal saber | El Ahly |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| **ANY WORD** | |
+--------------+------------------+
| khaled zein | Petroget |
+--------------+------------------+
| shady sameer | Petroget |
+--------------+------------------+
| wahed mahmoud| Petroget |
+--------------+------------------+
| samy shahen | Petroget |
+----+------+--+------------------+
| Mohamed gad | El Ahly |
+----+------+--+------------------+
| ehab zeyad | El Ahly |
+----+---------+------------------+
| moaz maged | El Ahly |
+--------------+------------------+
| mazen mahmod | El Ahly |
+--------------+------------------+
以此类推
group 16
group 32
group 64
group 128
group 256
已编辑:
我从 Gordon Linoff 那里得到了这个查询
select p.*
from (select p.*,
(@rn := if(@c = club_name, @rn + 1,
if(@c := club_name, 1, 1)
)
) as seqnum
from players p cross join
(select @c := '', @rn := 0) params
order by club_name
) p
order by floor((seqnum - 1) / 4), club_name
结合过滤后的数据:
select p.*
from (select p.full_name,club_name,
(@rn := if(@c = club_name, @rn + 1,
if(@c := club_name, 1, 1)
)
) as seqnum
from players p cross join
(select @c := '', @rn := 0) params WHERE `y_of_birth` LIKE N'%2000%'
order by club_name
) p
order by floor((seqnum - 1) / 4), club_name
输出类似的东西:
+----+------+---------------------+
| full_name | club_name |
+--------------+------------------+
| Ahmed Sayed | El Ahly |
+--------------+------------------+
| Kareem Gaber | El Ahly |
+--------------+------------------+
| Maher Zein | El Ahly |
+--------------+------------------+
| Mohab Saeed | El Ahly |
+----+------+--+------------------+
| kamal mado | Cocorico |
+--------------+------------------+
| hossam magdy | Cocorico |
+--------------+------------------+
| sayed ammar | Cocorico |
+--------------+------------------+
| karem gad | Cocorico |
+--------------+------------------+
| Mohamed gad | El Ahly |
+----+------+--+------------------+
| ehab zeyad | El Ahly |
+----+---------+------------------+
| moaz maged | El Ahly |
+--------------+------------------+
| mazen mahmod | El Ahly |
+--------------+------------------+
| shaker ali | Petroget |
+--------------+------------------+
| omar Saed | Petroget |
+--------------+------------------+
| moataz Gamal | Petroget |
+--------------+------------------+
| gamael zayed | Petroget |
+--------------+------------------+
| husein mazen | Cocorico |
+--------------+------------------+
| mazen kamal | Cocorico |
+--------------+------------------+
| maged ahmoud | Cocorico |
+--------------+------------------+
| mesho kareem | Cocorico |
+--------------+------------------+
| mano mazen | Petroget |
+--------------+------------------+
| shady srour | Petroget |
+--------------+------------------+
| mamdouh gamal| Petroget |
+--------------+------------------+
| khaled zein | Petroget |
+--------------+------------------+
| husein mazen | Cocorico |
+--------------+------------------+
| hassan maged | Cocorico |
+--------------+------------------+
| maged ahmoud | Cocorico |
+--------------+------------------+
| zakareya gad | Cocorico |
+--------------+------------------+
| shady sameer | Petroget |
+--------------+------------------+
| wahed mahmoud| Petroget |
+--------------+------------------+
| samy shahen | Petroget |
+----+------+--+------------------+
| abdo samy | Petroget |
+----+------+--+------------------+
任何帮助将不胜感激!
最佳答案
我阅读了您之前的帖子和这一篇。如果我明白了,最基本的事情是你有团队,你有球员,你想在某些标准化分组中显示数据(可以这么说)。
好吧,有一个恒定的数据,您总是将其与团队规模进行比较。
我会做的是创建一个子查询,将团队与球员计数分组,并以如下方式使用它:
select t.*
, x.total_players
-- , row_number() over(order by t.team_name) row_id
from team_table t
join (
select team_id
, count(1) total_playerss
from team_table
group by team_id
) x on x.team_id = t.team_id
order by t.team_name
当在 PHP 中回显结果集时,您可以构建一些函数,例如:
<?php
function add_some_word($playerCount) {
if ($playerCount >4 && $playerCount <= 8) {
echo '*** SOME WORD***';
echo '*** SOME WORD***';
echo '*** SOME WORD***';
}
else if ($playerCount >4 && $playerCount <= 8) {
echo '*** SOME WORD***';
echo '*** SOME WORD***';
}
// etc.
}
?>
使用结果集中的 row_id
,您可以看到团队何时开始和结束。
所以当它吐出行时,它可能是这样的:"
<?php
$currentTeamName = "";
while ($row = pg_fetch_array($result,null,PGSQL_ASSOC)) {
// echo data you would normally send out
if ($currentTeamName != $row['team_name']) {
add_some_word($row['total_players']);
}
}
?>
希望我答对了你的问题。我正在快速解决这个问题,但我认为它会有所帮助!
关于php/SQL - 在每 4 个名称之间打印多个单词 4 次,有很多条件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31573922/