php - fatal error : Call to undefined function mysqli_result()

Question

当我尝试将旧 sql 切换到 sqli 时，有人可以告诉我为什么这不起作用:

$query = "SELECT * FROM `product_category`";
$result = mysql_query($query, $connect) or die("could not perform query: " . mysql_error());
$num_rows = mysql_num_rows($result);

for ($i=0; $i < $num_rows; $i++)
{
    $ID = mysql_result($result,$i,"ID");
    $name = mysql_result($result,$i,"name");
    $description = mysql_result($result,$i,"description");

到:

$query = ("SELECT * FROM `product_category`");
$result = mysqli_query($connect, $query) or die("could not perform query");
$num_rows = mysqli_num_rows($result);

for ($i=0; $i < $num_rows; $i++)
{
    $ID = mysqli_result($result, "ID");
    $name = mysqli_result($result,$i,"name");
    $description = mysqli_result($result,$i,"description");`

它一直给我一个错误:“ fatal error :调用未定义的函数 mysqli_result()”

Answer 1

不要使用这种代码。这是非常低效的。使用 mysqli_fetch_assoc() 代替:

while($row = mysqli_fetch_assoc($result)) {
   $id = $row['ID'];
   $name = $row['name']; 
   etc..
}

一个 SINGLE 数据库操作，而不是您尝试执行的 3+ 个。