android - JSON - 与 Android 应用程序一起使用的单个文件

Question

我得到的这个应用程序需要屏幕上的四个位置保持最新(标题、地址、日期和图像来源)。

所以，我想也许我可以编写应用程序将读取的四个不同的 JSON 文件，如果我想更改应用程序显示的内容，我只需更改服务器上的那些 JSON 文件即可。

也许是这样的(file.json):

{"app": {
  "title": "Screen no. 1",
  "address": "Sesame Street",
  "date": "01-01-2014",
  "image": "http://myserver.com/image.jpg"
}}

在 Android 应用程序源中，当然会有 JSONParser 将从“http://myserver.com/file.json”获取信息。您认为这是否足够好或者是否有更好(且更简单)的解决方案？我尝试了解 Google Endpoints，但这确实很麻烦。

edit1:我已经从这里使用 JSONParser 自定义类:How to parse JSON in Android 在 Debug模式下，我发现要下载 file.json 中的值，因此我现在必须以某种方式读取它 - 它打印“获取地址:”但没有值:

Thread thread = new Thread(new Runnable(){
        @Override
        public void run() {
            try {
                Log.i("ABCDE", "Start Thread");
                //JSON
                JSONParser jparser = new JSONParser();
                JSONObject data = jparser.getJSONFromUrl("http://myserv.com/file.json");                
                Log.i("AbCDE", "Afer getting JSON");
                //JSONObject data = new JSONObject(myDataJson); 

                String address = "";

                try {
                    address = data.getString("address");
                } catch (JSONException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }

                Log.i("ABCDE", "Got the address: " + address);
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
    });

编辑2:我的XML突然停止工作(它验证并使层次结构树很好，但不是每次):

{
   "party1": {
      "title": "Screen no. 1",
      "address": "Sesame Street",
      "date": "01-01-2014",
      "image": "http://myserver.com/image.jpg",
      "destination": "somewhere"
   },
   "party2": {
      "title": "Screen no. 2",
      "address": "Oak Street",
      "date": "01-01-2014",
      "image": "http://myserver.com/image.jpg",
      "destination": "somewhere"
   },
   "party3": {
      "title": "Screen no. 1",
      "address": "Sesame Street",
      "date": "01-01-2014",
      "image": "http://myserver.com/image.jpg",
      "destination": "somewhere"
   },
   "party4": {
      "title": "Screen no. 1",
      "address": "Sesame Street",
      "date": "01-01-2014",
      "image": "http://myserver.com/image.jpg",
      "destination": "somewhere"
   }
}

JSON 验证器表示没问题或 SyntaxError:意外的标记。

这是我的 JSONParser.java 类:

public class JSONParser {

static InputStream is = null;
static JSONObject jObj = null;
static String json = "";

// constructor
public JSONParser() {}

public JSONObject getJSONFromUrl(String url) {

    // Making HTTP request
    try {
        // defaultHttpClient
        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost httpPost = new HttpPost(url);

        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();
        is = httpEntity.getContent();

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

    try {
        BufferedReader reader = new BufferedReader(new InputStreamReader(
                is, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();
        json = sb.toString();
    } catch (Exception e) {
        Log.e("Buffer Error", "Error converting result " + e.toString());
    }

    // try parse the string to a JSON object
    try {
        jObj = new JSONObject(json);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    }

    // return JSON String
    return jObj;

}

}

Answer 1

是的，从服务器获取数据作为 JSON 文件似乎是解决此问题的最佳且最轻量级的方法(尽管您提供的有关数据实际含义的数据很少)。

我建议使用org.json库，因为它允许你做这样的事情，减少解析时间:

String myDataJson = ... /* Obtain the data here */
long lastChangeTimestamp = ... /* Obtain the last saved timestamp, probably from SharedPrefs */

JSONObject data = new JSOBObject(myDataJson);

long newTimestamp = data.getLong("ts");
if(newTimestamp > lastChangeTimestamp){ 

String title = data.getString("title");
String address = data.getString("address");
String date = data.getString("date");
String image = data.getString("image");

/* Do somtehing with the newly obtained data and save the new timestamp to SharedPrefs */
}