java - 尝试插入 json 数组时出现数据插入错误？

Question

我正在尝试使用谷歌的volley库将json数组发送到mysql数据库。 以下是我发送的数据类型:-

[{"vatno":"","area":"Testing bay","status":"0","cstno":"","dbname":"webappdb","name":"ANUP BORDE","emp_role":"Manager","password":"1223","key":"","city":"Pune","shop_name":"Test Shop","mobile":"8600931386"}]

我收到数据插入错误，如下所示:-

Data insertion errorYou have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key,dbname,status,role)VALUES( '', 'ANUP BORDE', '8600931386', '1223', 'Test Sho' at line 1

我正在尝试运行这个 php 脚本。

<?php

        include "config.php";
        $dbname ="goldmine";
        $con = mysqli_connect($server_name,$mysql_user,$mysql_pass,$dbname);
         if(!$con)
         {
           echo "Connection Error".mysqli_connect_error();
         }
         else{
        //echo "";
         }

        $arrAssoc = json_decode(stripslashes($_POST['jsonarray']), true);
        $values="";
        foreach($arrAssoc as $aa){
                $values.="(";
                $values.=" '".$aa['']."',";
                $values.=" '".$aa['name']."',";
                $values.=" '".$aa['mobile']."',";
                $values.=" '".$aa['password']."',";
                $values.=" '".$aa['shop_name']."',";
                $values.=" '".$aa['area']."',";
                $values.=" '".$aa['city']."',";
                $values.=" '".$aa['vatno']."',";
                $values.=" '".$aa['cstno']."',";
                $values.=" '".$aa['key']."',";
                $values.=" '".$aa['dbname']."',";
                $values.=" '".$aa['status']."',";
                $values.=" '".$aa['role']."'";
                $values.="),";
        }
        $values=rtrim($values,',');
                //Insert into goldmine_users (name,mobile,password,role)Values('Anup','8600931386','123','admin');

        $query="INSERT INTO goldmine_users(name,mobile,password,shop_name,area,city,vatno,cstno,key,dbname,status,role)VALUES".$values;

        if(mysqli_query($con,$query))
        {
        echo "Data inserted";
        }else
        {
       echo "Data insertion error".mysqli_error($con);
        }


?>

这是我将数据发送到 mysql 数据库的 volley 代码。

public void registerUser()
{
    final String jsonArray = rolejson.toString().trim();
    Log.d("JSON RESPONSE",jsonArray);
    StringRequest stringReq = new StringRequest(Request.Method.POST, REGISTERUSER, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {

            Log.d("USER INFO RESPONSE",response);
        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {

        }
    }){
        @Override
        protected Map<String, String> getParams() throws AuthFailureError {
            Log.d("LOG_USERINFO", jsonArray);
            Map<String, String> params = new HashMap<>();
            params.put(KEY_JSONARRAY, jsonArray);
            return params;
        }
    };

    RequestQueue rq = Volley.newRequestQueue(this);
    rq.add(stringReq);
}

这就是我的数据库的样子:-

欢迎任何帮助或建议。我认为我在某个地方犯了一个愚蠢的错误，如果有人能指导我找到正确的解决方案，那就太好了。

Answer 1

 $query="INSERT INTO goldmine_users(name,mobile,password,shop_name,area,city,vatno,cstno,key,dbname,status,role)VALUES".$values;

key 是保留关键字，因此应该用反引号(或类似的东西)转义

 $query="INSERT INTO goldmine_users(`name`,`mobile`,`password`,`shop_name`,`area`,`city`,`vatno`,`cstno`,`key`,`dbname`,`status`,`role`)VALUES".$values;