java - Android - 在Fragment中显示WebView

Question

所以我在 XML 布局文件中有一个包含以下内容的 fragment :

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    tools:context="com.example.dwinnbrown.myapplicationv20.MainFragment">

    <!-- TODO: Update blank fragment layout -->
    <WebView
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:id="@+id/webView"
        android:layout_alignParentTop="true"
        android:layout_alignParentStart="true"
        android:layout_alignParentBottom="true"
        android:layout_alignParentEnd="true" />

</RelativeLayout>

我现在尝试通过与 fragment 关联的 java 文件将 url 加载到 Web View 中。但是我遇到了错误“无法解析 findViewByID(int)”。有什么想法吗？

这是我尝试用于 fragment 的代码:

import android.os.Bundle;
import android.support.v4.app.Fragment;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.webkit.WebView;


/**
 * A simple {@link Fragment} subclass.
 */
public class MainFragment extends Fragment {

    public MainFragment() {
        // Required empty public constructor
    }


    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {
        // Inflate the layout for this fragment
        return inflater.inflate(R.layout.fragment_main, container, false);


        String url = "http://winn-brown.co.uk/";
        WebView view = (WebView) this.findViewById(R.id.webView);
        view.getSettings().setJavaScriptEnabled(true);
        view.loadUrl(url);
    }



}

Answer 1

做这样的事情

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {

    View rootView = inflater.inflate(R.layout.fragment_main, container, false);

    String url = "http://winn-brown.co.uk/";
    WebView view = (WebView) rootView.findViewById(R.id.webView);
    view.getSettings().setJavaScriptEnabled(true);
    view.loadUrl(url);

    return rootView ;
}