java - android 如何处理url中的空格

Question

当我尝试在 url android 中运行一些空格时出现错误， 这是代码:

              String strUrlLoginFullpath = "";


              strUrlLoginFullpath = strUrlMain+"exl?u="+strUser+"&p="+strPass+"&t=1";



              URL url = new URL(strUrlLoginFullpath);
              publishProgress(40);

              //membuka koneksi
              URLConnection urlConn = url.openConnection();
              urlConn.setConnectTimeout(50000);
              urlConn.setReadTimeout(50000);

              //digunakan untuk menangkap nilai dari server
              BufferedReader in = new BufferedReader(
                      new InputStreamReader(
                              urlConn.getInputStream()));
              publishProgress(60);
              String inputLine;
              int i=0;
              while ((inputLine = in.readLine()) != null)
              {     
                  Log.v("Login",i+", return:" +inputLine+"; url: "+strUrlLoginFullpath);
                  if(i == 5)
                      {
                        Log.v("Login","RESULT >"+i+", return:" +inputLine+"; url: "+strUrlLoginFullpath);
                        str2 = inputLine;
                      }
                  i++;
              }
              in.close();


              publishProgress(80);

              publishProgress(100);
          } 
          catch (MalformedURLException e) 
          {
                Log.v("KxL", "MalformedURLException=" + e.toString());
          } 
          catch (IOException e) 
          {
                Log.v("KxL", "IOException=" + e.toString());
          } 
          return null;
    }

如您所见..我有在 strUrlLoginFullpath = strUrlMain+"exl?u="+strUser+"&p="+strPass+"&t=1"; 中进行登录验证的命令，但有条件strUser 有时包含空格，这会使我的程序无法运行。那么如何解决这个问题呢？

Answer 1

URLEncoder.encode()您的 URL 参数值，以便正确编码空格和其他特殊字符。

示例:

strUrlLoginFullpath = strUrlMain + "exl?u=" + URLEncoder.encode(strUser, "UTF-8") +
    "&p=" + URLEncoder.encode(strPass, "UTF-8") + "&t=1";