MySQL DATE_ADD 用法，5 天间隔

Question

我正在尝试在单个查询中选择 5 天内的订单总金额 ($) 和发票计数。不过，我似乎无法做到这一点。我当前的查询在这里...

SELECT
    COUNT(id) as invoice_count,
    SUM(orderTotal) as orders_sum,
    UNIX_TIMESTAMP(created) as created
FROM ids_invoice
WHERE DATE_ADD(created, INTERVAL +1 DAY)
AND userId = 23 LIMIT 5'

我不完全确定 DATE_ADD 是我正在寻找的正确函数。

目前我正在......

Array ( 
    [0] => Array ( 
        [invoice_count] => 420
        [orders_total] => 97902.90
        [created] => 1252596560
    )
)

Array ( 
    [0] => Array ( 
        [invoice_count] => 68
        [orders_total] => 14193.20
        [created] => 1262900809
    )
)

我想要一些更像...的东西

Array ( 
    [0] => Array ( 
        [invoice_count] => 18
        [orders_total] => 4902.90
        [date] => 04-19-2010
    )
)

Array ( 
    [0] => Array ( 
        [invoice_count] => 12
        [orders_total] => 5193.20
        [date] => 04-20-2010
    )
)

我对 mysql 日期函数还很陌生，所以也许我在浏览 mysql 文档时错过了我需要的函数。

更新 我已经更新了我的查询......这仍然没有为有发票的每一天拉一行。只有当 20 日有符合 userId 条件的发票时，才会提取 19 日的发票。

SELECT
    COUNT(id) as invoice_count,
    SUM(orderTotal) as orders_sum,
    UNIX_TIMESTAMP(created) as created
FROM ids_invoice
WHERE
    created BETWEEN "2010-04-19 00:00:00" AND DATE_ADD("2010-04-19 00:00:00", INTERVAL +5 DAY) AND
    userId = 17

Answer 1

要获取日期跨度之间的记录，请使用:

WHERE created BETWEEN NOW() AND DATE_ADD(NOW(), INTERVAL 5 DAY)

此示例将为您获取从今天到 future 几天的记录(假设今天存在任何记录，包括时间)。如果您想回到过去，请查看 DATE_SUB。