package com.sample.downloadImage;
import java.io.BufferedInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLConnection;
import org.apache.http.util.ByteArrayBuffer;
import android.app.Activity;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.os.Bundle;
import android.widget.ImageView;
public class downloadImage extends Activity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Bitmap bitmap = DownloadImage("http://www.allindiaflorist.com/imgs/arrangemen4.jpg");
ImageView img = (ImageView) findViewById(R.id.img);
img.setImageBitmap(bitmap);
}
private InputStream OpenHttpConnection(String urlString)
throws IOException
{
InputStream in = null;
int response = -1;
URL url = new URL(urlString);
URLConnection conn = url.openConnection();
if (!(conn instanceof HttpURLConnection))
throw new IOException("Not an HTTP connection");
try{
HttpURLConnection httpConn = (HttpURLConnection) conn;
httpConn.setAllowUserInteraction(false);
httpConn.setInstanceFollowRedirects(true);
httpConn.setRequestMethod("GET");
httpConn.connect();
response = httpConn.getResponseCode();
if (response == HttpURLConnection.HTTP_OK) {
in = httpConn.getInputStream();
}
}
catch (Exception ex)
{
throw new IOException("Error connecting");
}
return in;
}
private Bitmap DownloadImage(String URL)
{
Bitmap bitmap = null;
InputStream in = null;
try {
in = OpenHttpConnection(URL);
BufferedInputStream bis = new BufferedInputStream(in, 8190);
ByteArrayBuffer baf = new ByteArrayBuffer(50);
int current = 0;
while ((current = bis.read()) != -1)
{
baf.append((byte)current);
}
byte[] imageData = baf.toByteArray();
bitmap =BitmapFactory.decodeByteArray(imageData, 0, imageData.length);
in.close();
}
catch (IOException e1)
{
e1.printStackTrace();
}
return bitmap;
}
}
想要从服务器检索图像,所以我尝试在服务器中发布图像并通过网址检索,但它适用于小图像,当涉及超过 60kb 的大图像时,有人可以提供解决问题的想法吗
package com.sample.downloadImage;
import java.io.BufferedInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLConnection;
import org.apache.http.util.ByteArrayBuffer;
import android.app.Activity;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.os.Bundle;
import android.widget.ImageView;
public class downloadImage extends Activity {
HttpURLConnection httpConn;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Bitmap bitmap = DownloadImage("http://www.allindiaflorist.com/imgs/arrangemen4.jpg");
ImageView img = (ImageView) findViewById(R.id.img);
img.setImageBitmap(bitmap);
}
private InputStream OpenHttpConnection(String urlString)
throws IOException
{
InputStream in = null;
int response = -1;
URL url = new URL(urlString);
URLConnection conn = url.openConnection();
if (!(conn instanceof HttpURLConnection))
throw new IOException("Not an HTTP connection");
try{
httpConn = (HttpURLConnection) conn;
httpConn.setAllowUserInteraction(false);
httpConn.setInstanceFollowRedirects(true);
httpConn.setRequestMethod("GET");
httpConn.connect();
response = httpConn.getResponseCode();
if (response == HttpURLConnection.HTTP_OK) {
in = httpConn.getInputStream();
DownloadImage(urlString);
}
}
catch (Exception ex)
{
throw new IOException("Error connecting");
}
return in;
}
private Bitmap DownloadImage(String URL)
{
Bitmap bitmap = null;
//InputStream is = null;
InputStream in;
try
{
in = httpConn.getInputStream();
BufferedInputStream bis = new BufferedInputStream(in, 3 *1024);
ByteArrayBuffer baf = new ByteArrayBuffer(50);
int current = 0;
while ((current = bis.read()) != -1)
{
baf.append((byte)current);
byte[] imageData = baf.toByteArray();
bitmap =BitmapFactory.decodeByteArray(imageData, 0, imageData.length);
return bitmap;
}
}
catch (IOException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
return bitmap;
}
}
最佳答案
表格:Load Large Image from server on Android
当您直接将 BitmapFactory.decodeFromStream() 连接到远程连接的 InputStream 时,BitmapFactory.decodeFromStream() 放弃并仅返回 null 的情况并不罕见。在内部,如果您没有向该方法提供 BufferedInputStream,它会将提供的流包装在缓冲区大小为 16384 的流中。有时有效的一种选择是传递具有较大缓冲区大小的 BufferedInputStream,例如:
BufferedInputStream bis = new BufferedInputStream(is, 32 * 1024); 更普遍有效的方法是先完整下载文件,然后像这样解码数据:
InputStream is = connection.getInputStream();
BufferedInputStream bis = new BufferedInputStream(is, 8190);
ByteArrayBuffer baf = new ByteArrayBuffer(50);
int current = 0;
while ((current = bis.read()) != -1) {
baf.append((byte)current);
}
byte[] imageData = baf.toByteArray();
BitmapFactory.decodeByteArray(imageData, 0, imageData.length);
仅供引用,此示例中的缓冲区大小有些任意。正如其他答案中所说,不要将这么大的图像在内存中保留的时间比您需要的时间长,这是一个很棒的主意。您可以考虑将其直接写入文件并显示下采样版本。
希望有帮助!
关于android - 从服务器检索图像到 Android 应用程序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10550349/