java - 按值对 HashMap 进行排序

标签 java sorting hashmap

我需要根据存储在其中的值对我的 HashMap 进行排序。 HashMap 包含存储在手机中的联系人姓名。

我还需要在对值进行排序后立即自动对键进行排序,或者您可以说键和值绑定(bind)在一起,因此值的任何更改都应反射(reflect)在键中。

HashMap<Integer,String> map = new HashMap<Integer,String>();
map.put(1,"froyo");
map.put(2,"abby");
map.put(3,"denver");
map.put(4,"frost");
map.put(5,"daisy");

需要的输出:

2,abby;
5,daisy;
3,denver;
4,frost;
1,froyo;

最佳答案

Map 排序方法的通用版本类似于:

private static <K extends Comparable<K>, V extends Comparable<V>> Map<K, V> sort(
        final Map<K, V> unsorted,
        final boolean order) {
    final var list = new LinkedList<>(unsorted.entrySet());

    list.sort((o1, o2) -> order
                          ? o1.getValue().compareTo(o2.getValue()) == 0
                            ? o1.getKey().compareTo(o2.getKey())
                            : o1.getValue().compareTo(o2.getValue())
                          : o2.getValue().compareTo(o1.getValue()) == 0
                            ? o2.getKey().compareTo(o1.getKey())
                            : o2.getValue().compareTo(o1.getValue()));
    return list.stream().collect(
            Collectors.toMap(
                    Entry::getKey, Entry::getValue, (a, b) -> b, LinkedHashMap::new
            )
    );
}

以下代码提供按值升序和降序排序:

import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
import java.util.LinkedHashMap;
import java.util.LinkedList;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;

public class SortMapByValue
{
    public static final boolean ASC = true;
    public static final boolean DESC = false;

    public static void main(String[] args)
    {

        // Creating dummy unsorted map
        Map<String, Integer> unsortMap = new HashMap<String, Integer>();
        unsortMap.put("B", 55);
        unsortMap.put("A", 80);
        unsortMap.put("D", 20);
        unsortMap.put("C", 70);

        System.out.println("Before sorting......");
        printMap(unsortMap);

        System.out.println("After sorting ascending order......");
        Map<String, Integer> sortedMapAsc = sortByComparator(unsortMap, ASC);
        printMap(sortedMapAsc);
        
        
        System.out.println("After sorting descindeng order......");
        Map<String, Integer> sortedMapDesc = sortByComparator(unsortMap, DESC);
        printMap(sortedMapDesc);

    }

    private static Map<String, Integer> sortByComparator(Map<String, Integer> unsortMap, final boolean order)
    {

        List<Entry<String, Integer>> list = new LinkedList<Entry<String, Integer>>(unsortMap.entrySet());

        // Sorting the list based on values
        Collections.sort(list, new Comparator<Entry<String, Integer>>()
        {
            public int compare(Entry<String, Integer> o1,
                    Entry<String, Integer> o2)
            {
                if (order)
                {
                    return o1.getValue().compareTo(o2.getValue());
                }
                else
                {
                    return o2.getValue().compareTo(o1.getValue());

                }
            }
        });

        // Maintaining insertion order with the help of LinkedList
        Map<String, Integer> sortedMap = new LinkedHashMap<String, Integer>();
        for (Entry<String, Integer> entry : list)
        {
            sortedMap.put(entry.getKey(), entry.getValue());
        }

        return sortedMap;
    }

    public static void printMap(Map<String, Integer> map)
    {
        for (Entry<String, Integer> entry : map.entrySet())
        {
            System.out.println("Key : " + entry.getKey() + " Value : "+ entry.getValue());
        }
    }
}

使用较新的 Java 功能:

 import java.util.*;
 import java.util.Map.Entry;
 import java.util.stream.Collectors;
    
 public class SortMapByValue

 {
    private static final boolean ASC = true;
    private static final boolean DESC = false;
    public static void main(String[] args)
    {

        // Creating dummy unsorted map
        Map<String, Integer> unsortMap = new HashMap<>();
        unsortMap.put("B", 55);
        unsortMap.put("A", 20);
        unsortMap.put("D", 20);
        unsortMap.put("C", 70);

        System.out.println("Before sorting......");
        printMap(unsortMap);

        System.out.println("After sorting ascending order......");
        Map<String, Integer> sortedMapAsc = sortByValue(unsortMap, ASC);
        printMap(sortedMapAsc);


        System.out.println("After sorting descending order......");
        Map<String, Integer> sortedMapDesc = sortByValue(unsortMap, DESC);
        printMap(sortedMapDesc);
    }

    private static Map<String, Integer> sortByValue(Map<String, Integer> unsortMap, final boolean order)
    {
        List<Entry<String, Integer>> list = new LinkedList<>(unsortMap.entrySet());

        // Sorting the list based on values
        list.sort((o1, o2) -> order ? o1.getValue().compareTo(o2.getValue()) == 0
                ? o1.getKey().compareTo(o2.getKey())
                : o1.getValue().compareTo(o2.getValue()) : o2.getValue().compareTo(o1.getValue()) == 0
                ? o2.getKey().compareTo(o1.getKey())
                : o2.getValue().compareTo(o1.getValue()));
        return list.stream().collect(Collectors.toMap(Entry::getKey, Entry::getValue, (a, b) -> b, LinkedHashMap::new));

    }

    private static void printMap(Map<String, Integer> map)
    {
        map.forEach((key, value) -> System.out.println("Key : " + key + " Value : " + value));
    }
}

关于java - 按值对 HashMap 进行排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8119366/

相关文章:

java - 如何使用java 8按 'name'对对象进行分组?

java - Spring安全/授权级别

java - 重载真的是 Java 中获取方法参数默认值的唯一方法吗?

java - java接口(interface)冲突

ios - 按字母顺序对 UItableview 中的数据进行排序的最简单方法

java - 在Java中存储键值对的最佳方式是什么?

java - 如何获取 HashMap<String, Object> 中特定键的值的子集initialMap = new HashMap<String, Object>()

java - Android 4.4.2 不删除文件

java - 自定义 TableHeaderUI 破坏了自定义 TableRowSorter

javascript - 如何对javascript中的字符串进行数字排序