我正在尝试将用户的输入发送到 php 脚本以使其最终传递到 SQL 服务器,大多数代码运行但在提交数据时遇到问题。
@IBAction func submit(_ sender: AnyObject) {
let requestURL = URL(string: "*****")
let request = NSMutableURLRequest(url:requestURL!)
request.httpMethod = "POST"
let song=txt1.text!
let artist=txt2.text!
let album=txt3.text!
let year=txt4.text!
let genre=txt5.text!
let songPost = "song=" + (song as String)
let artistPost = "&artist=" + (artist as String)
let albumPost = "&album=" + (album as String)
let yearPost = "&year=" + (year as String)
let genrePost = "&genre=" + (genre as String)
request.httpBody = songPost.data(using: String.Encoding.utf8);
request.httpBody = artistPost.data(using: String.Encoding.utf8);
request.httpBody = albumPost.data(using: String.Encoding.utf8);
request.httpBody = yearPost.data(using: String.Encoding.utf8);
request.httpBody = genrePost.data(using: String.Encoding.utf8);
--->>let task = URLSession.shared.dataTask(with: request) { data, response, error in
guard let data = data, error == nil else { // check for fundamental networking error
print("error=\(error)")
print(response)
return
}
if let httpStatus = response as? HTTPURLResponse, httpStatus.statusCode != 200 { // check for http errors
print("statusCode should be 200, but is \(httpStatus.statusCode)")
print("response = \(response)")
}
let responseString = String(data: data, encoding: .utf8)
print("responseString = \(responseString)")
}
task.resume()
urlsession.shared.datatask 代码行有问题。编译器错误显示“对 member'dataTask(with:completionhandler:) 的模糊引用”
什么可以使此代码起作用?我如何验证此信息是否已在应用程序上传递?
最佳答案
您收到该错误消息的原因是因为您在需要 URLRequest
的地方传递了 NSMutableURLRequest
。
改变这一行:
let request = NSMutableURLRequest(url:requestURL!)
为此:
var request = URLRequest(url:requestURL!)
应该修复它。
但我建议多做一些修复,以使您的请求成功发送到服务器:
let requestURL = URL(string: "*****")
//You should use `URLRequest` in Swift 3, mutability is represented by `var`
var request = URLRequest(url:requestURL!)
request.httpMethod = "POST"
//UITextField.text can be nil, you should treat nil cases
//(Generally avoid using forced unwrapping `!` as far as you can.)
let song = txt1.text ?? ""
let artist = txt2.text ?? ""
let album = txt3.text ?? ""
let year = txt4.text ?? ""
let genre = txt5.text ?? ""
//`song`,... are all Strings, you have no need to add `as String`
let songPost = "song=" + song
let artistPost = "&artist=" + artist
let albumPost = "&album=" + album
let yearPost = "&year=" + year
let genrePost = "&genre=" + genre
//You need to make a single data containing all params
//(Creating a concatenated String and getting `data` later would be another way.)
var data = Data()
data.append(songPost.data(using: String.Encoding.utf8)!)
data.append(artistPost.data(using: String.Encoding.utf8)!)
data.append(albumPost.data(using: String.Encoding.utf8)!)
data.append(yearPost.data(using: String.Encoding.utf8)!)
data.append(genrePost.data(using: String.Encoding.utf8)!)
request.httpBody = data
let task = URLSession.shared.dataTask(with: request) { data, response, error in
...
关于php - 快速 3 http 请求,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40096687/