我有一个 UIView
,每次我在另一个 View 中按下按钮时都会显示它
@IBOutlet weak var view1: UIView!
@IBOutlet weak var view2: UIView!
@IBAction func showView(_ sender: Any) {
view2.isHidden = false
}
我想要的是添加一个点击手势,允许我在每次点击 View 外部时隐藏 view2,并且由于这些 View 是可拖动的,我希望第二个 View 在隐藏时不可点击(这样如果我在我的视线下触摸我不会冒险移动它。 这是我尝试过的:
-
var gesture : UITapGestureRecognizer? override func viewDidLoad() { super.viewDidLoad() NotificationCenter.default.addObserver(self, selector: #selector(closeView), name: NSNotification.Name("CloseView"), object: nil) gesture = UITapGestureRecognizer(target: self, action: #selector(ViewController.closeView)) } @objc func closeView() { if view2.isHidden == false { view2.isUserInteractionEnabled = true view2.isHidden = false self.view.removeGestureRecognizer(gesture!) } else { view2.isHidden = true view2.isUserInteractionEnabled = true self.view.addGestureRecognizer(gesture!) } }
-
let closeTapGesture = UITapGestureRecognizer(target: view, action: #selector(getter: view2.isHidden) view.addGestureRecognizer(closeTapGesture)
这些都不起作用,我该怎么办?
最佳答案
您需要检查您是否确实在 view2 之外点击:
var gesture : UITapGestureRecognizer?
override func viewDidLoad() {
super.viewDidLoad()
NotificationCenter.default.addObserver(self,
selector: #selector(closeView), name: NSNotification.Name("CloseView"), object: nil)
let gesture = UITapGestureRecognizer(target: self, action: #selector(closeView(_:)))
view.addGestureRecognizer(gesture)
self.gesture = gesture
}
@objc private func closeView(_ tapGestureRecognizer: UITapGestureRecognizer) {
let location = tapGestureRecognizer.location(in: view2)
guard view2.isHidden == false,
!view2.bounds.contains(location) else { //We need to have tapped outside of view 2
return
}
view2.isHidden = true
}
关于ios - 如何在点击 Swift4 时关闭 UIView,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55165014/