java - Gson 忽略值 = null 的 map 条目

Question

Gson gson = new Gson();

Map<String,Object> map = new HashMap<String, Object>();
map.put("a", 1);
map.put("b", null);

System.out.println(gson.toJson(map)); //prints {"a":1}

如何让它包含所有条目？

Answer 1

见 Gson User Guide - Null Object Support :

The default behaviour that is implemented in Gson is that null object fields are ignored. This allows for a more compact output format; however, the client must define a default value for these fields as the JSON format is converted back into its Java form.

Here's how you would configure a Gson instance to output null:

Gson gson = new GsonBuilder().serializeNulls().create();