我有一个计算麦克风输入的 fft 的函数。 目标是在我调用 run 函数时创建一个框架,我用所有波段生成了 float 组。
现在一切正常,但我不知道如何从 gotSomeAudio 函数返回运行函数中的数组。
非常感谢您的帮助
@objc
public class FFT:NSObject{
var audioInput: TempiAudioInput!
@objc
public func run() -> Array<Float>{
let audioInputCallback: TempiAudioInputCallback = { (numberOfFrames, timeStamp, inout samples: [Float]) -> Void in
self.gotSomeAudio(numberOfFrames, timeStamp: timeStamp, samples: samples)
}
audioInput = TempiAudioInput(audioInputCallback: audioInputCallback, sampleRate: 44100, numberOfChannels: 1)
audioInput.startRecording()
// how can i return the Array from the gotSomeAudio function?
return xyz
}
@objc
public func gotSomeAudio(numberOfFrames: Int, timeStamp: Double, samples: [Float]) -> Array<Float> {
let fft = TempiFFT(withSize: numberOfFrames, sampleRate: 44100)
// Setting a window type reduces errors
fft.windowType = TempiFFTWindowType.hanning
// Perform the FFT
fft.fftForward(samples)
// Map FFT data to logical bands. This gives 4 bands per octave across 7 octaves = 28 bands.
//fft.calculateLogarithmicBands(minFrequency: 100, maxFrequency: 11025, bandsPerOctave: 4)
//fft.calculateLinearBands(minFrequency: 0, maxFrequency: fft.nyquistFrequency, numberOfBands: Int(screenWidth))
fft.calculateLogarithmicBands(minFrequency: 100, maxFrequency: 11025, bandsPerOctave: 4)
// Process some data
return fft.bandFrequencies
}
}
最佳答案
您可以将其传递给回调函数:
public func run(complete: Array<Float> -> Void) {
let audioInputCallback: TempiAudioInputCallback = { (numberOfFrames, timeStamp, inout samples: [Float]) -> Void in
complete(self.gotSomeAudio(numberOfFrames, timeStamp: timeStamp, samples: samples))
}
...
myInstance.run() { floatArray in
// Use floatArray here.
}
关于ios - 如何返回 void 函数的值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37961960/