ios - 作用于所有类的通用方法

Question

我有类

class Citizen{

    var name:String
    var age:Int
    var lawPrevilige = 0

    init(name:String,age:Int){

        self.name = name
        self.age = age
    }
}

class Politician{

    var name:String
    var age:Int
    var lawPrevilige = 1

    init(name:String,age:Int){

        self.name = name
        self.age = age
    }

}

还有一个类来操纵这些

class PoliceDept{

    var departMentName = "InterPol"
    var departMentAddress:String = "Earth"

    //this method should be able to access object of any class with the same properties.
    func investigateAnyOne(person:AnyObject){


        if let p = person as? Citizen{

            print(p.name)


        }else if let po =  person as? Politician{

            print(po.name)
        }
    }
}

现在的问题是，如果我有一个类 Disabled People、UnderAge People 等具有确切的属性名称和年龄..那么我如何制作方法 警察部门的 investigateAnyOne 在没有类型转换的情况下对 AnyObject 进行操作。这可能吗？

向下转换为 10-12 个类的每种类型的对象会使代码变得困惑。我是否应该创建多个 if else 语句来检查类的类型或任何其他符合协议(protocol)的方式。

问题是如果有许多其他类型的人我想调查，我该怎么办..

Answer 1

创建一个Protocol 并在其中定义所有属性，并在所有类中遵循Common Protocol。因此您无需在 investigateAnyOne 中检查多个案例。

protocol Common {
var name:String {get set}
var age:Int {get set}
 var lawPrevilige:Int {get set}

}

class Politician: Common{

 var name:String
 var age:Int
 var lawPrevilige = 1

 init(name:String,age:Int){

 self.name = name
 self.age = age
 }

}

class PoliceDept{

 var departMentName = "InterPol"
 var departMentAddress:String = "Earth"


 func investigateAnyOne(person: Common){
   self.departMentName = person.name
  }
}

创建一个 Politician 对象并将其传递给 investigateAnyOne 方法。

let politician = Politician(name: "demo", age: 10)
let policeDept = PoliceDept()
 policeDept.investigateAnyOne(politician)