MySQL - 如何插入具有多对多关系的表

Question

我有一张人 table 。每个人都有属性(property)，许多人可能拥有某种属性(property)。所以这是一个多对多的关系。这是架构:

CREATE TABLE persons (
  person_id int(11) NOT NULL AUTO_INCREMENT,
  firstname varchar(30) NOT NULL,
  lastname varchar(30) NOT NULL,
  PRIMARY KEY (person_id)
);

CREATE TABLE properties (
  property_id int(11) NOT NULL AUTO_INCREMENT,
  property varchar(254) NOT NULL UNIQUE,
  PRIMARY KEY (property_id)
);

CREATE TABLE has_property (
  person_id int(11) NOT NULL,
  property_id int(11) NOT NULL,
  PRIMARY KEY (person_id,property_id),
  FOREIGN KEY (person_id) REFERENCES persons (person_id),
  FOREIGN KEY (property_id) REFERENCES properties (property_id)
);

现在假设我想将这个人插入到数据库中:

• 名字:'约翰'
• 姓氏:'Doe'
• 属性:'property_A','property_B','property_C'

人

+-----------+-----------+----------+
| person_id | firstname | lastname |
+-----------+-----------+----------+
|         1 | John      | Doe      |
+-----------+-----------+----------+

属性

+-------------+------------+
| property_id |  property  |
+-------------+------------+
|           1 | property_A |
|           2 | property_B |
|           3 | property_C |
+-------------+------------+

has_property

+-----------+-------------+
| person_id | property_id |
+-----------+-------------+
|         1 |           1 |
|         1 |           2 |
|         1 |           3 |
+-----------+-------------+

到目前为止，我认为最好的事情是在persons表中进行常规插入:

INSERT INTO persons (firstname,lastname) VALUES ('John','Doe');

然后进行选择以找到我刚刚插入的人的 id

SELECT person_id FROM persons WHERE firstname='John' AND lastname='Doe';

为了插入其他两个表(因为我需要知道 person_id)。 但我认为一定有更好的方法，不是吗？

Answer 1

这就是我最终要做的。我希望它可以帮助某人。

INSERT INTO persons (firstname,lastname) VALUES ('John','Doe');
SET @person_id = LAST_INSERT_ID();

INSERT IGNORE INTO properties (property) VALUES ('property_A');
SET @property_id = LAST_INSERT_ID();
INSERT INTO has_property (person_id,property_id) VALUES(@person_id, @property_id);

INSERT IGNORE INTO properties (property) VALUES ('property_B');
SET @property_id = LAST_INSERT_ID();
INSERT INTO has_property (person_id,property_id) VALUES(@person_id, @property_id);

INSERT IGNORE INTO properties (property) VALUES ('property_C');
SET @property_id = LAST_INSERT_ID();
INSERT INTO has_property (person_id,property_id) VALUES(@person_id, @property_id);