swift - swift 重复一个功能

Question

我制作了这个抖动功能来尝试为我的游戏中的菜单标题添加抖动效果。以为我觉得这是一个很长的路要走!有没有更短/更简洁的方法来执行这样的重复操作？

还有可能让这个永远重复吗？

func shakeMenu(){

    DispatchQueue.main.asyncAfter(deadline: .now() + .seconds(2), execute:
        {

    let moveNodeRight = SKAction.moveBy(x: 7.0, y: 0.0, duration: 0.05)
    let moveNodeLeft = SKAction.moveBy(x: -7.0, y: 0.0, duration: 0.05)
    let moveNodeRight1 = SKAction.moveBy(x: 7.0, y: 0.0, duration: 0.05)
    let moveNodeLeft1 = SKAction.moveBy(x: -7.0, y: 0.0, duration: 0.05)
    let moveNodeRight2 = SKAction.moveBy(x: 7.0, y: 0.0, duration: 0.05)
    let moveNodeLeft2 = SKAction.moveBy(x: -7.0, y: 0.0, duration: 0.05)
    let moveNodeRight3 = SKAction.moveBy(x: 7.0, y: 0.0, duration: 0.05)
    let moveNodeLeft3 = SKAction.moveBy(x: -7.0, y: 0.0, duration: 0.05)
    let moveNodeRight4 = SKAction.moveBy(x: 7.0, y: 0.0, duration: 0.05)


    self.shake = SKAction.sequence([moveNodeRight, moveNodeLeft, moveNodeRight1, moveNodeLeft1, moveNodeRight2, moveNodeLeft2, moveNodeLeft3, moveNodeRight3, moveNodeRight4])
    self.menu.run(self.shake)

    })
}





func shakeMenu(){

    let moveRight: SKAction = .moveBy(x: 7.0, y: 0.0, duration: 0.05)
    let sequence: SKAction = .sequence([moveRight, moveRight.reversed()]
    self.menu.run(.repeat(sequence), count: 4)

}

Answer 1

SKAction.repeatForever ( https://developer.apple.com/reference/spritekit/skaction/1417676-repeatforever ) 怎么样

这样你就可以写:

let moveNodeRight = SKAction.moveBy(x: 7.0, y: 0.0, duration: 0.05)
let moveNodeLeft = SKAction.moveBy(x: -7.0, y: 0.0, duration: 0.05)
let moveSequence = SKAction.sequence([moveNodeRight, moveNodeLeft])
let moveForever = SKAction.repeatForever(moveSequence)

self.menu.run(moveForever)

希望对你有帮助。