javascript - 使用 Javascript 在对象中查找重复值

Question

我一直在努力解决我遇到的问题。我有一个包含对象的数组，如下所示:

var array = [
  {
    name: "Steven Smith",
    Country: "England",
    Age: 35
  },
  {
    name: "Hannah Reed",
    Country: "Scottland",
    Age: 23
  },
  {
    name: "Steven Smith",
    Country: "England",
    Age: 35
  },
  {
    name: "Robert Landley",
    Country: "England",
    Age: 84
  },
  {
    name: "Steven Smith",
    Country: "England",
    Age: 35
  },
  {
    name: "Robert Landley",
    Country: "England",
    Age: 84
  }
];

我想获取其中具有重复值的对象，并基于要搜索的值。即，我想获得具有重复值“name”和“age”但没有“country”的对象，所以我最终会得到:

[
  {
    name: "Steven Smith",
    Country: "England",
    Age: 35
  },
  {
    name: "Steven Smith",
    Country: "England",
    Age: 35
  },
  {
    name: "Robert Landley",
    Country: "England",
    Age: 84
  },
  {
    name: "Steven Smith",
    Country: "England",
    Age: 35
  },
  {
    name: "Robert Landley",
    Country: "England",
    Age: 84
  }
];

如果一直在努力做

array.forEach(function(name, age){
  if(array.name == name || array.age == age){
    console.log(the result)
}
})

但这只会检查对象的值是否等于它们自身。

谁能帮帮我？

Answer 1

您可以使用 2 个reduce。第一个是对数组进行分组。第二种是仅包括具有 1 个以上元素的组。

var array = [{"name":"Steven Smith","Country":"England","Age":35},{"name":"Hannah Reed","Country":"Scottland","Age":23},{"name":"Steven Smith","Country":"England","Age":35},{"name":"Robert Landley","Country":"England","Age":84},{"name":"Steven Smith","Country":"England","Age":35},{"name":"Robert Landley","Country":"England","Age":84}]

var result = Object.values(array.reduce((c, v) => {
  let k = v.name + '-' + v.Age;
  c[k] = c[k] || [];
  c[k].push(v);
  return c;
}, {})).reduce((c, v) => v.length > 1 ? c.concat(v) : c, []);

console.log(result);