我有这个函数可以进行 ajax 调用。我在最后一段代码注释中描述了这个问题。
function doop(){
var that = this;
var theold = "theold";
var thenew = "thenew";
$.ajax({
url: 'doop.php',
type: 'POST',
data: 'before=' + theold + '&after=' + thenew,
success: function(resp) {
if(resp == 1) {
$(that).siblings('.theold').html(thenew);
}
}
});
// I have some code here (out of the ajax) that **further** changes
// the .theold's html beyond what it was changed inside ajax success
// but the change depends on whether the resp (inside the success
// function) returned 1 or not, so this code out here depends on the ajax
// so it looks like I have to turn this ajax call into a sync ajax
return false;
}
根据代码注释中描述的问题,对于这种情况最好进行哪些更改?
最佳答案
您需要为这样的同步请求设置 async: false:
function doop(){
var that = this;
var theold = $(this).siblings('.theold').html();
var thenew = $(this).siblings('.thenew').val();
$.ajax({
async: false,
url: 'doop.php',
type: 'POST',
data: 'before=' + theold + '&after=' + thenew,
success: function(resp) {
if(resp == 1) {
$(that).siblings('.theold').html(thenew);
}
}
});
// some other code
return false;
}
参见 here详情
关于javascript - ajax jquery同步回调成功,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/1572610/