php - 有人入侵了我的数据库 - 如何？

Question

有人入侵了我的数据库并删除了表。

在我的 PHP 页面中，我使用 mysql_real_escape_string 有一个查询:

$db_host="sql2.netsons.com";
$db_name="xxx";
$username="xxx";
$password="xxx";    

$db_con=mysql_connect($db_host,$username,$password);    

$connection_string=mysql_select_db($db_name);
mysql_connect($db_host,$username,$password);    
mysql_set_charset('utf8',$db_con); 

$email= mysql_real_escape_string($_POST['email']);
$name= mysql_real_escape_string($_POST['name']);
$sex= mysql_real_escape_string($_POST['sex']);    

if($_POST['M']!=""){  $sim = 1;  }else {  $sim = 0;   }

$query = "INSERT INTO `users` (`email`, `name`, `sex`, `M`) VALUES
( '".$email."', '".ucwords(strtolower($name))."', '".$sex."','".$sim."')";    

$res = mysql_query($query) or die("Query fail: " . mysql_error() );

mysql_close($db_con);

并且 register_globals 被禁用。

那么，我的数据库是如何被黑的？

Answer 1

mysql_real_escape_string

The MySQL connection. If the link identifier is not specified, the last link opened by mysql_connect() is assumed. If no such link is found, it will try to create one as if mysql_connect() was called with no arguments. If no connection is found or established, an E_WARNING level error is generated.

在这里解释:Does mysql_real_escape_string() FULLY protect against SQL injection?

根据您的代码片段，您已经连接了两次数据库。

$db_con=mysql_connect($db_host,$username,$password);    

$connection_string=mysql_select_db($db_name);
mysql_connect($db_host,$username,$password);    
mysql_set_charset('utf8',$db_con); 

而且您没有提供数据库链接标识符:

$email= mysql_real_escape_string($_POST['email']);
$name= mysql_real_escape_string($_POST['name']);
$sex= mysql_real_escape_string($_POST['sex']); 

因此，mysql_set_charset 对为多字节字符提供的真正转义$_POST 没有影响。

建议

• 去掉第二个mysql_connect($db_host,$username,$password);
• 在执行mysql_real_escape_string
时显式添加$db_con