我有一个 dd/mm/yyyy 格式的不同日期的下拉列表，我想将所选日期转换为 javascript 日期格式并使用 javascript 递增 1。谁能帮帮我吗。提前致谢。
这是我的代码:
HTML
<select name="txtweek" id="txtweek">
<option>--select--</option>
<option>31-08-2015</option>
<option>07-09-2015</option>
<option>14-09-2015</option>
<option>21-09-2015</option>
<option>28-09-2015</option>
<option>05-10-2015</option>
<option>12-10-2015</option>
<option>19-10-2015</option>
</select>
Javascript
jQuery("#txtweek").change(function(){
if(jQuery("select[name='txtuser'] option:selected").text()=='--select--'){
alert("Please select a user first to proceed");
return false;
} else {
jQuery.ajax({
url:ajaxurl,
type:'post',
data:{action:'timecardapp_manage_timecard_stepone',user_id: jQuery("#txtuser").val()},
success: function(response){
var data=JSON.parse(response);
var currentweek = jQuery("#txtweek").val();
var finalcurrentweek = new Date(currentweek);
var next_day = finalcurrentweek.setDate(finalcurrentweek.getDate()+1);;
var trHTML = '';
jQuery.each(data.final_data, function (i, item) {
if(item.event_title == 'Admin'){
//Monday
trHTML += '<tr>';
trHTML += '<td>'+item.event_title+'</td>';
trHTML += '<td>Mon</td>';
trHTML += '<td> </td>';
trHTML += '<td> </td>';
trHTML += '<td>'+item.start_date+'</td>';
trHTML += '<td>'+item.end_date+'</td>';
trHTML += '<td> </td>';
trHTML += '<td> </td>';
trHTML += '<td>'+item.expense_allowance_value+'</td>';
trHTML += '<td>'+item.hours_allowed+'</td>';
trHTML += '</tr>';
//Tuesday
trHTML += '<tr>';
trHTML += '<td>'+item.event_title+'</td>';
trHTML += '<td>Tue</td>';
trHTML += '<td> </td>';
trHTML += '<td> </td>';
trHTML += '<td>'+item.start_date+'</td>';
trHTML += '<td>'+item.end_date+'</td>';
trHTML += '<td> </td>';
trHTML += '<td> </td>';
trHTML += '<td>'+item.expense_allowance_value+'</td>';
trHTML += '<td>'+item.hours_allowed+'</td>';
trHTML += '</tr>';
//Wednesday
trHTML += '<tr>';
trHTML += '<td>'+item.event_title+'</td>';
trHTML += '<td>Wed</td>';
trHTML += '<td> </td>';
trHTML += '<td> </td>';
trHTML += '<td>'+item.start_date+'</td>';
trHTML += '<td>'+item.end_date+'</td>';
trHTML += '<td> </td>';
trHTML += '<td> </td>';
trHTML += '<td>'+item.expense_allowance_value+'</td>';
trHTML += '<td>'+item.hours_allowed+'</td>';
trHTML += '</tr>';
//Thursday
trHTML += '<tr>';
trHTML += '<td>'+item.event_title+'</td>';
trHTML += '<td>Thu</td>';
trHTML += '<td> </td>';
trHTML += '<td> </td>';
trHTML += '<td>'+item.start_date+'</td>';
trHTML += '<td>'+item.end_date+'</td>';
trHTML += '<td> </td>';
trHTML += '<td> </td>';
trHTML += '<td>'+item.expense_allowance_value+'</td>';
trHTML += '<td>'+item.hours_allowed+'</td>';
trHTML += '</tr>';
//Friday
trHTML += '<tr>';
trHTML += '<td>'+item.event_title+'</td>';
trHTML += '<td>Fri</td>';
trHTML += '<td> </td>';
trHTML += '<td> </td>';
trHTML += '<td>'+item.start_date+'</td>';
trHTML += '<td>'+item.end_date+'</td>';
trHTML += '<td> </td>';
trHTML += '<td> </td>';
trHTML += '<td>'+item.expense_allowance_value+'</td>';
trHTML += '<td>'+item.hours_allowed+'</td>';
trHTML += '</tr>';
} else{
trHTML += '<tr>';
trHTML += '<td>'+item.event_title+'</td>';
trHTML += '<td>'+item.day_of_week+'</td>';
trHTML += '<td> </td>';
trHTML += '<td> </td>';
trHTML += '<td>'+item.start_date+'</td>';
trHTML += '<td>'+item.end_date+'</td>';
trHTML += '<td> </td>';
trHTML += '<td> </td>';
trHTML += '<td>'+item.expense_allowance_value+'</td>';
trHTML += '<td>'+item.hours_allowed+'</td>';
trHTML += '</tr>';
}
});
// var trHTML = '';
jQuery('.timecard-step2').find('tbody').empty();
jQuery('.timecard-step2').find('tbody').append(trHTML);
}
});
}
});
最佳答案
像这样:
function pad(str) {
return ("0"+str).slice(-2);
}
function getNextDay(str) {
var parts = str.split("-");
var next_day = new Date(parts[2], parts[1] - 1, parseInt(parts[0], 10) + 1, 12, 0, 0, 0);
return ""+pad(next_day.getDate())+"-"+pad(next_day.getMonth()+1)+"-"+next_day.getFullYear();
}
var currentweek = jQuery("#txtweek option:selected").text(), // no values available
next_day = new Date(); // or some other default
if (currentweek && currentweek.indexOf("--") == -1) { // not the first
next_day=getNextDay(currentweek);
console.log(currentweek + '->'+next_day);
}
例子:
function pad(str) {
return ("0"+str).slice(-2);
}
function getNextDay(str) {
var parts = str.split("-");
var next_day = new Date(parts[2], parts[1] - 1, parseInt(parts[0], 10) + 1, 12, 0, 0, 0);
return ""+pad(next_day.getDate())+"-"+pad(next_day.getMonth()+1)+"-"+next_day.getFullYear();
}
$(function() {
$("#txtweek").on("change",function() {
var currentweek = jQuery("#txtweek option:selected").text(), // no values available
next_day = new Date(); // or some other default
if (currentweek && currentweek.indexOf("--") == -1) { // not the first
next_day =getNextDay(currentweek);
snippet.log(currentweek + '->'+next_day);
}
});
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src="http://tjcrowder.github.io/simple-snippets-console/snippet.js"></script>
<select name="txtweek" id="txtweek">
<option>--select--</option>
<option>31-08-2015</option>
<option>07-09-2015</option>
<option>14-09-2015</option>
<option>21-09-2015</option>
<option>28-09-2015</option>
<option>05-10-2015</option>
<option>12-10-2015</option>
<option>19-10-2015</option>
</select>关于javascript - 如何将日期从下拉列表转换为 javascript 日期格式并增加 1 天？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/33280936/