<分区>
这是我的:
Scanner input = new Scanner(System.in);
System.out.print("Enter a year: ");
int Year = input.nextInt();
System.out.print("Enter a month (first three letters with the first"
+ " letter uppercase): ");
String Month = input.next();
String ThirtyOne = "Jan" + "Mar" + "May" + "Jul" + "Aug" + "Oct" + "Dec";
String DaysThirtyOne = ThirtyOne.substring(21) + "31";
String Thirty = "Apr" + "Jun" + "Sep" + "Nov";
String DaysThirty = Thirty.substring(12) + "30";
String TwentyEight = "Feb";
String DaysTwentyEight = TwentyEight.substring(3) + "28";
String DaysLeapYear = TwentyEight.substring(3) + "29";
boolean isLeapYear = ((Year % 4 == 0) && (Year % 100 != 0) && (Year % 400 == 0));
if (ThirtyOne.contains(Month)) {
System.out.println(Month + " " + Year + " has " + DaysThirtyOne
+ " days in it.");
}
if (Thirty.contains(Month)) {
System.out.println(Month + " " + Year + " has " + DaysThirty
+ " days in it.");
}
if(TwentyEight.contains(Month)) {
System.out.println(Month + " " + Year + " has " + DaysTwentyEight
+ " days in it.");
}
if (isLeapYear) {
System.out.println(Month + " " + Year + " has " + DaysLeapYear
+ " days in it.");
}
我是编程新手，所以如果这段代码看起来不成熟，我不会感到惊讶。无论如何，我让用户输入一年和一个月(前三个字母)。我为闰年创建了一个 boolean 变量，它表示用户输入的任何年份都需要被 4、100 和 400 整除。然后，我创建了一个 if 语句来判断是否是闰年以打印出“Feb(无论是哪一年)用户输入)中有 DaysLeapYear。”我认为我的算法有问题，因为如果我取出 TwentyEight 的 if 语句并只保留闰年 if 语句，计算机甚至不会打印出如果是闰年，二月会有多少天.再一次，我认为我的算法出了问题，但它可能在其他地方，我希望再看看这个，看看是否有人看到了我不是的东西，毕竟我是新手。