我有一对一关系的下课
@Entity
@Table(name = "PERSON")
public class Person {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "PERSON_ID")
private int personId;
@Column(name = "PERSON_NAME", nullable = false, length = 30)
private String personName;
@OneToOne(mappedBy = "person", cascade = CascadeType.ALL)
private DrivingLicense drivingLicense;
}
@Entity
@Table(name = "DRIVING_LICENSE")
public class DrivingLicense {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "LICENSE_NUMBER")
private int licenseNumber;
@Column(name = "DATE_OF_ISSUE")
private Date dateOfIssue;
@OneToOne
@JoinColumn(name = "PERSON_ID", unique = true)
private Person person;
}
目前每个表有3行
但是当我像下面这样对 person
进行查询时
Query query = entityManager.createQuery("from Person p");
在获得结果列表后,它导致了太多的查询,如下所示;
Hibernate: select person0_.PERSON_ID as PERSON_ID1_1_, person0_.PERSON_NAME as PERSON_NAME2_1_ from PERSON person0_
Hibernate: select drivinglic0_.LICENSE_NUMBER as LICENSE_NUMBER1_0_1_, drivinglic0_.DATE_OF_ISSUE as DATE_OF_ISSUE2_0_1_, drivinglic0_.PERSON_ID as PERSON_ID3_0_1_, person1_.PERSON_ID as PERSON_ID1_1_0_, person1_.PERSON_NAME as PERSON_NAME2_1_0_ from DRIVING_LICENSE drivinglic0_ left outer join PERSON person1_ on drivinglic0_.PERSON_ID=person1_.PERSON_ID where drivinglic0_.PERSON_ID=?
Hibernate: select drivinglic0_.LICENSE_NUMBER as LICENSE_NUMBER1_0_1_, drivinglic0_.DATE_OF_ISSUE as DATE_OF_ISSUE2_0_1_, drivinglic0_.PERSON_ID as PERSON_ID3_0_1_, person1_.PERSON_ID as PERSON_ID1_1_0_, person1_.PERSON_NAME as PERSON_NAME2_1_0_ from DRIVING_LICENSE drivinglic0_ left outer join PERSON person1_ on drivinglic0_.PERSON_ID=person1_.PERSON_ID where drivinglic0_.PERSON_ID=?
Hibernate: select drivinglic0_.LICENSE_NUMBER as LICENSE_NUMBER1_0_1_, drivinglic0_.DATE_OF_ISSUE as DATE_OF_ISSUE2_0_1_, drivinglic0_.PERSON_ID as PERSON_ID3_0_1_, person1_.PERSON_ID as PERSON_ID1_1_0_, person1_.PERSON_NAME as PERSON_NAME2_1_0_ from DRIVING_LICENSE drivinglic0_ left outer join PERSON person1_ on drivinglic0_.PERSON_ID=person1_.PERSON_ID where drivinglic0_.PERSON_ID=?
很明显,为了获取 3 行,hibernate 触发了 4 个查询,如何解决这个问题?我在人际关系方面做错了什么吗?
更新
现在如果我像这样获取驾驶执照
Query query = entityManager.createQuery("from DrivingLicense dl");
更糟糕的是,触发了 7 个查询。
最佳答案
要拥有独立于 JPA 供应商的解决方案,您可以使用以下 JPQL 查询。
获取所有拥有DrivingLicense
的Person
Query query = entityManager.createQuery("from Person p join fetch p.drivingLicense");
让所有 Person
独立,无论他们是否有 DrivingLicense
Query query = entityManager.createQuery("from Person p left join fetch p.drivingLicense");
或使用Criteria API
CriteriaBuilder criteriaBuilder = em.getCriteriaBuilder();
CriteriaQuery<Person> criteriaQuery = criteriaBuilder.createQuery(Person.class);
Root<Person> root = criteriaQuery.from(Person.class);
root.fetch("drivingLicense", JoinType.INNER);
criteriaQuery.select(root);
List<Person> resultList = em.createQuery(criteriaQuery).getResultList();
回复
CriteriaBuilder criteriaBuilder = em.getCriteriaBuilder();
CriteriaQuery<Person> criteriaQuery = criteriaBuilder.createQuery(Person.class);
Root<Person> root = criteriaQuery.from(Person.class);
root.fetch("drivingLicense", JoinType.LEFT);
criteriaQuery.select(root);
List<Person> resultList = em.createQuery(criteriaQuery).getResultList();
关于java - 一对一关系 hibernate 导致许多查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32644033/