这是我的 spring 安全 Bean
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<http auto-config="true">
<intercept-url pattern="/welcome*" access="ROLE_USER" />
<form-login login-page="/login" default-target-url="/welcome"
authentication-failure-url="/loginfailed" />
<logout logout-success-url="/logout" />
</http>
<authentication-manager>
<authentication-provider>
<user-service>
<user name="username" password="123456" authorities="ROLE_USER" />
</user-service>
</authentication-provider>
</authentication-manager>
</beans:beans>
这是我的 MVC 调度程序 servlet
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.1.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.1.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd">
<mvc:annotation-driven />
<tx:annotation-driven />
<context:annotation-config />
<context:component-scan base-package="com.apsas" />
<!-- Required for body marshalling -->
<mvc:resources mapping="resources/**" location="/WEB-INF/resources/" />
<bean id="entityManager"
class="org.springframework.orm.jpa.support.SharedEntityManagerBean">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean">
<property name="persistenceUnitName" value="apsaspu" />
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<bean
class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass">
<value>
org.springframework.web.servlet.view.tiles2.TilesView
</value>
</property>
</bean>
<bean id="tilesConfigurer"
class="org.springframework.web.servlet.view.tiles2.TilesConfigurer">
<property name="definitions">
<list>
<value>/WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
</beans>
这是我的 web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://www.oracle.com/webfolder/technetwork/jsc/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>Spring MVC Application</display-name>
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/mvc-dispatcher-servlet.xml,
/WEB-INF/spring-security.xml</param-value>
</context-param>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
这是我的 Controller
@Controller
@RequestMapping(value = "/c")
public class MainController {
@RequestMapping(value = "/welcome", method = RequestMethod.GET)
public String printWelcome(ModelMap model, Principal principal) {
String name = principal.getName();
model.addAttribute("username", name);
model.addAttribute("message", "Spring Security Custom Form example");
return "hello";
}
@RequestMapping(value = "/login", method = RequestMethod.GET)
public String login(ModelMap model) {
return "login";
}
@RequestMapping(value = "/loginfailed", method = RequestMethod.GET)
public String loginerror(ModelMap model) {
model.addAttribute("error", "true");
return "login";
}
@RequestMapping(value = "/logout", method = RequestMethod.GET)
public String logout(ModelMap model) {
return "login";
}
}
我的问题是当我访问 localhost:8080/apsas/c/welcome 时我得到了
HTTP ERROR 500
Server Error
java.lang.NullPointerException
at com.apsas.controller.MainController.printWelcome(MainController.java:30)
我可以成功进入登录页面，但在单击我收到的提交按钮后，我收到 http 错误 404 访问/apsas/c/j_spring_security_check 时出现问题。
这是日志 警告:在名称为“mvc-dispatcher”的 DispatcherServlet 中找不到带有 URI [/apsas/c/j_spring_security_check] 的 HTTP 请求的映射
我可以成功访问我的磁贴中定义的某些页面，除了应该引导我登录的欢迎。请帮忙
最佳答案
默认的spring security登录页面是[application context]/j_spring_security_check
您的登录页面正在提交到 /apsas/c/j_spring_security_check。假设您的应用上下文是 apsas，您的登录表单应该提交给 /apsas/j_spring_security_check 或 ../j_spring_security_check。
明确地说，这是登录页面上 form 元素的 action 属性的值。如果您需要帮助，请将您的登录页面发布到问题中，我可以更具体一些。
关于java - 在 DispatcherServlet 中找不到具有 URI j_spring_security_check 的 HTTP 请求的映射，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/20390057/