我有这样的实体:
@Entity
@Table(name = "ASSESSMENT")
public class Assessment {
//All other fields..
@OneToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL, mappedBy = "assessment")
@OrderBy(value = "order ASC")
private List<AssessmentPart> assessmentParts = new LinkedList<>();
public List<AssessmentPart> getAssessmentParts() {
return assessmentParts;
}
//All other getters/setters
}
另一个:
@Entity
@Table(name = "ASSESSMENT_PART")
public class AssessmentPart {
//All other fields
@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "ASSESSMENT_ID", nullable = false)
private Assessment assessment;
public Assessment getAssessment() {
return assessment;
}
public void setAssessment(Assessment assessment) {
this.assessment = assessment;
}
//All other getters/setters
}
评估部分是从评估实体延迟加载的。我还有 spring Controller 方法,它是事务性的,并从数据库加载评估部分:
@Transactional
public void doSomething(String partId, Map<String, Object> model) {
AssessmentPart assessmentPart = //laods a part with entity manager
Assessment assessment = assessmentPart.getAssessment(); //Getting the assessments
model.put("assessmentParts", assessment.getAssessmentParts()); //adding all assessments parts into spring model map
}
一旦我将评估部分添加到 spring 模型映射中,它们就可以在我的 JSP 页面中使用,我正在使用 JSTL 循环遍历它们:
<c:forEach var="assessmentPart" items="${assessmentParts}">
//Not loading any lazy stuff, just getting an ID of assessment part
</c:forEach>
此 JSP 页面抛出异常:
org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: my.package.something.Assessment.assessmentParts, could not initialize proxy - no Session
如果此集合已加载到事务中,这怎么可能?我只是想遍历,此时 hibernate 不应该加载任何东西,因为它已经加载了。为什么会发生这种奇怪的事情?
最佳答案
在 View 中,entitymanager 已经关闭,因此您集合中的元素无法检索那里的属性。您在 Controller 中编写的代码不会初始化集合中的元素(它是一个 LAZY 集合),而只会初始化集合(而不是其中的元素)。
通过在您的 Web 配置中配置 OpenEntityManagerInViewFilter
强制实体管理器保持打开状态。
或者更改您的 Controller 代码以包含对 Hibernate.initialize
的调用以正确初始化您的集合。
@Transactional
public void doSomething(String partId, Map<String, Object> model) {
AssessmentPart assessmentPart = //laods a part with entity manager
Assessment assessment = assessmentPart.getAssessment(); //Getting the assessments
Hibernate.initialize(assesment.getAssesmentParts()); // Init collection
model.put("assessmentParts", assessment.getAssessmentParts()); //adding all assessments parts into spring model map
}
或者创建一个自定义查询,强制预先获取集合。
关于java - 在 Spring JSP 页面中使用集合时出现 Hibernate LazyInitializationException,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19047835/