Java:掷两个骰子直到得到想要的总和

Question

我想编写一个程序，我掷两个骰子，直到我得到这些骰子的总和为 11。我想记录在我得到总和时我使用了多少次“尝试”或掷骰子11.

到目前为止我的代码:

public class Dice {

    public static void main(String[] args) {

    int counter1 = 0; //Amount of rolls player 1 took to get sum of 9
    int P1sum = 0;

    do {
        int P1Die1 = (int)(Math.random()*6)+1;
        int P1Die2 = (int)(Math.random()*6)+1;  
        P1sum = (P1Die1 + P1Die2);
        counter1++;
    } while (P1sum == 11);

        System.out.println("Player 1 took "+counter1+" amount of rolls to have a sum of 11.");  
    }
}

它只是不断地打印出需要 1 卷才能得到 11 的总和，所以有些地方不对。

我的目标:让玩家 1 继续掷骰子 2，直到我的总和为 11，并记录它尝试了多少次。然后让玩家 2 做同样的事情。然后，无论哪个玩家的尝试次数较少，都会“赢得”游戏。

帮助感谢感谢我是新手

Answer 1

你可能想更新你的条件

while (P1sum == 11) // this results in false and exit anytime your sum is not 11

到

while (P1sum != 11) // this would execute the loop until your sum is 11